>> from datetime import datetime
>> now = datetime.now()
>> now.strftime('%Y-%m-%d')
'2018-01-29'

如果此时我们想转换为 2018-1-29的形式,有如下的两种方式:

  • 法 1:分别转换为 int 型以消除前导 0:

    year = str(int(now.strftime('%Y')))
    month = str(int(now.strftime('%m')))
    day = str(int(now.strftime('%d')))
    year+'-'+month+'-'+day
  • 法二:使用 datetime 下的结构体:

    >> now = now.timetuple()
    >> now
    time.struct_time(tm_year=2018, tm_mon=1, tm_mday=29, tm_hour=0, tm_min=24, tm_sec=0, tm_wday=0, tm_yday=29, tm_isdst=-1)
    
    >> year = str(now.tm_year)
    >> month = str(now.tm_mon)
    >> day = str(now.tm_mday)
    
posted on 2018-01-29 00:34  未雨愁眸  阅读(898)  评论(0编辑  收藏  举报