Factorial Trailing Zeroes

Given an integer n, return the number of trailing zeroes in n!.

Note: Your solution should be in logarithmic time complexity.

 

public class Solution {
    public int trailingZeroes(int n) {
        int sum=0;
        while(n/5!=0){
            sum=sum+n/5;
            n=n/5;
        }
        return sum;
    }
}

 

posted @ 2015-01-25 20:20  mrpod2g  阅读(86)  评论(0编辑  收藏  举报