POJ2352 Stars

嘟嘟嘟

 

二维偏序。

按y排序,在x方向上用树状数组维护前缀和。

因为输入保证排好序了,所以y没什么用。

x可以等于0,所以最好在输入的时候加1,否则会TLE……

 1 #include<cstdio>
 2 #include<iostream>
 3 #include<cmath>
 4 #include<algorithm>
 5 #include<cstring>
 6 #include<cstdlib>
 7 #include<cctype>
 8 #include<vector>
 9 #include<stack>
10 #include<queue>
11 using namespace std;
12 #define enter puts("") 
13 #define space putchar(' ')
14 #define Mem(a, x) memset(a, x, sizeof(a))
15 #define rg register
16 typedef long long ll;
17 typedef double db;
18 const int INF = 0x3f3f3f3f;
19 const db eps = 1e-8;
20 const int maxn = 3.2e4 + 5;
21 inline ll read()
22 {
23   ll ans = 0;
24   char ch = getchar(), last = ' ';
25   while(!isdigit(ch)) {last = ch; ch = getchar();}
26   while(isdigit(ch)) {ans = ans * 10 + ch - '0'; ch = getchar();}
27   if(last == '-') ans = -ans;
28   return ans;
29 }
30 inline void write(ll x)
31 {
32   if(x < 0) x = -x, putchar('-');
33   if(x >= 10) write(x / 10);
34   putchar(x % 10 + '0');
35 }
36 
37 int n, ans[maxn];
38 
39 int c[maxn];
40 int lowbit(int x)
41 {
42   return x & -x;
43 }
44 void add(int pos)
45 {
46   for(; pos < maxn; c[pos]++, pos += lowbit(pos));
47 }
48 int query(int pos)
49 {
50   int ret = 0;
51   for(; pos; ret += c[pos], pos -= lowbit(pos));
52   return ret;
53 }
54 
55 int main()
56 {
57   n = read();
58   for(int i = 1; i <= n; ++i)
59     {
60       int x = read() + 1, y = read();
61       ans[query(x)]++;
62       add(x);
63     }
64   for(int i = 0; i < n; ++i) write(ans[i]), enter;
65   return 0;
66 }
View Code

 

posted @ 2018-10-16 09:45  mrclr  阅读(134)  评论(0编辑  收藏  举报