hdu 1754 简单的线段树应用
本来想找些树状数组的题做做,看到这题,不知道用树状数组的话应该如何做,就还是用线段树了。
/*
* hdu1754/win.cpp
* Created on: 2011-9-6
* Author : ben
*/
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <algorithm>
using namespace std;
const int MAXN = 200100;
const int MAX_NODE = 400100;
int N, M, nCount;
int scores[MAXN];
typedef struct CNode {
int L, R;
int maxscore;
CNode *pLeft, *pRight;
} CNode;
CNode Tree[MAX_NODE];
inline int mymax(int a, int b) {
return a > b ? a : b;
}
//建立线段树
void BuildTree(CNode *pRoot, int L, int R) {
pRoot->L = L;
pRoot->R = R;
if (L == R) {
pRoot->maxscore = scores[L];
return;
}
nCount++;
pRoot->pLeft = Tree + nCount;
nCount++;
pRoot->pRight = Tree + nCount;
int mid = (L + R) / 2;
BuildTree(pRoot->pLeft, L, mid);
BuildTree(pRoot->pRight, mid + 1, R);
pRoot->maxscore = mymax(pRoot->pLeft->maxscore, pRoot->pRight->maxscore);
}
//插入数据
void Update(CNode *pRoot, int index) {
if (pRoot->L == pRoot->R) {
pRoot->maxscore = scores[index];
return;
}
int mid = (pRoot->L + pRoot->R) / 2;
if (index <= mid) {
Update(pRoot->pLeft, index);
} else {
Update(pRoot->pRight, index);
}
pRoot->maxscore = mymax(pRoot->pLeft->maxscore, pRoot->pRight->maxscore);
}
int Query(CNode *pRoot, int from, int to) {
if (pRoot->L == from && pRoot->R == to) {
return pRoot->maxscore;
}
int mid = (pRoot->L + pRoot->R) / 2;
if (mid >= from && mid < to) {
int m1, m2;
m1 = Query(pRoot->pLeft, from, mid);
m2 = Query(pRoot->pRight, mid + 1, to);
return mymax(m1, m2);
} else if (mid >= to) {
return Query(pRoot->pLeft, from, to);
} else {
return Query(pRoot->pRight, from, to);
}
}
void work();
int main() {
#ifndef ONLINE_JUDGE
freopen("data.in", "r", stdin);
#endif
work();
return 0;
}
void work() {
char op;
int a, b;
while (scanf("%d%d", &N, &M) == 2) {
for (int i = 1; i <= N; i++) {
scanf("%d", &scores[i]);
}
nCount = 0;
BuildTree(Tree, 1, N);
for (int i = 0; i < M; i++) {
scanf(" %c", &op);
if (op == 'Q') {
scanf("%d%d", &a, &b);
printf("%d\n", Query(Tree, a, b));
} else {
scanf("%d%d", &a, &b);
scores[a] = b;
Update(Tree, a);
}
}
}
}