CTF-SHOW RE3

拿到题目分析

moke@moke:/mnt/d/ctf/ctf-show$ file r3
r3: ELF 64-bit LSB shared object, x86-64, version 1 (SYSV), dynamically linked, interpreter /lib64/ld-linux-x86-64.so.2, for GNU/Linux 3.2.0, BuildID[sha1]=db369095e7d1408227569c73862f91eb3fb4a2e8, not stripped

  • DEV 调试 v16=0xE560

v16先加上v17[6]，然后判断是否大于0xffff，小于等于0xffff即退出循环
这里可以直接让v17[6]=0xffff-0xE560=0x1A9F，v16加上0x1A9F后即等于0xffff，然后退出循环

moke@moke:/mnt/d/ctf/ctf-show$ ./r3
plz input the key:
000001a9f0
OK
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posted @ 2021-08-02 16:27  墨客moke  阅读(937)  评论(2)  编辑  收藏  举报