python 正则表达式
python 正则表达式示例：
1 #re.py 2 import re 3 4 ''' 5 m = re.match(r'^\d{3}\-\d{3,8}$', '010-12345') 6 print(m.group(0)) 7 8 test = '正则表达式' 9 if re.match(r'正则表达式', test): 10 print('ok') 11 else: 12 print('failed') 13 14 #吧字符串切分成规则的list 15 s = 'a b c'.split(' ') 16 print(s) 17 18 l = re.split(r'\s+', 'a b c') 19 print(l) 20 21 l = re.split(r'[\s\,]+', 'a,b, , ,c') 22 print(l) 23 24 #编译,生成一个规则，用来处理目标字符串 25 #group()返回匹配结果，0:原始字符串，1、2....按顺序返回匹配到的结果 26 re_telephone = re.compile(r'^(\d{3})-(\d{3,8})$') 27 #使用 28 #s=re_telephone.match('010-12345').groups() 29 s=re_telephone.match('010-12345') 30 print(s.group(0)) 31 print(s.group(1)) 32 print(s.group(2)) 33 ''' 34 35 import re 36 def is_valid_email(addr): 37 # str=r'^[a-zA-Z0-9_]+(\.[a-zA-Z0-9_]+){0,4}@[a-zA-Z0-9_-]+(\.[a-zA-Z0-9_-]+){0,4}$' 38 str=r'^[a-zA-Z0-9_]+(\.[a-zA-Z0-9_]+){0,4}@[a-zA-Z0-9_-]+(\.[a-zA-Z0-9_-]+){1,4}$' 39 if re.match(str, addr): 40 return True 41 42 print(is_valid_email('a@szclou.com')) 43 print(is_valid_email('###aaaa.aaa@szclou.com.org')) 44 45 #IPv4匹配公式 (?=(\b|\D))(((\d{1,2})|(1\d{1,2})|(2[0-4]\d)|(25[0-5]))\.){3}((\d{1,2})|(1\d{1,2})|(2[0-4]\d)|(25[0-5]))(?=(\b|\D)) 46 #ipv6匹配公式 ^([\\da-fA-F]{1,4}:){7}([\\da-fA-F]{1,4})$ 47 48 #https://docs.python.org/3/library/re.html?highlight=re#module-re
