(easy)LeetCode 225.Implement Stack using Queues
Posted on 2015-07-30 20:25 骄阳照林 阅读(162) 评论(0) 编辑 收藏 举报Implement the following operations of a stack using queues.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- empty() -- Return whether the stack is empty.
Notes:
- You must use only standard operations of a queue -- which means only
push to back
,peek/pop from front
,size
, andis empty
operations are valid. - Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
Update (2015-06-11):
The class name of the Java function had been updated to MyStack instead of Stack.
Credits:
Special thanks to @jianchao.li.fighter for adding this problem and all test cases.
解析:java 中,Queue接口可使用的函数有 offer(E e):添加到队列尾 peek():查看队列头 poll():删除队头元素 remove()移除队头元素
另外:Deque接口中的push(),pop()操作均是在队头操作。
代码如下:
class MyStack { // Push element x onto stack. Queue<Integer> q1=new LinkedList<Integer>(); Queue<Integer> q2=new LinkedList<Integer>(); public void push(int x) { q1.offer(x); } // Removes the element on top of the stack. public void pop() { while(q1.size()>1) q2.offer(q1.poll()); q1.poll(); Queue<Integer> q=q1; q1=q2; q2=q; } // Get the top element. public int top() { while(q1.size()>1) q2.offer(q1.poll()); int x=q1.poll(); q2.offer(x); Queue<Integer>q=q1; q1=q2; q2=q; return x; } // Return whether the stack is empty. public boolean empty() { return q1.isEmpty(); } }
运行结果: