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(easy)LeetCode 225.Implement Stack using Queues

Posted on 2015-07-30 20:25  骄阳照林  阅读(162)  评论(0编辑  收藏  举报

Implement the following operations of a stack using queues.

  • push(x) -- Push element x onto stack.
  • pop() -- Removes the element on top of the stack.
  • top() -- Get the top element.
  • empty() -- Return whether the stack is empty.

Notes:

  • You must use only standard operations of a queue -- which means only push to backpeek/pop from frontsize, and is empty operations are valid.
  • Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
  • You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).

 

Update (2015-06-11):
The class name of the Java function had been updated to MyStack instead of Stack.

Credits:
Special thanks to @jianchao.li.fighter for adding this problem and all test cases.

解析:java 中,Queue接口可使用的函数有 offer(E e):添加到队列尾  peek():查看队列头  poll():删除队头元素 remove()移除队头元素

         另外:Deque接口中的push(),pop()操作均是在队头操作。

代码如下:

class MyStack {
    // Push element x onto stack.
    Queue<Integer> q1=new LinkedList<Integer>();
    Queue<Integer> q2=new LinkedList<Integer>();
    
    public void push(int x) {
        q1.offer(x);
    }

    // Removes the element on top of the stack.
    public void pop() {
        while(q1.size()>1) q2.offer(q1.poll());
        q1.poll();
        Queue<Integer> q=q1;
        q1=q2;
        q2=q;
        
    }

    // Get the top element.
    public int top() {
      while(q1.size()>1) q2.offer(q1.poll());
      int x=q1.poll();
      q2.offer(x);
      Queue<Integer>q=q1;
      q1=q2;
      q2=q;
      return x;
    }

    // Return whether the stack is empty.
    public boolean empty() {
        return q1.isEmpty();
    }
}

  运行结果: