数据转换-整数字节数组

任务详情

0. 在openEuler(推荐)或Ubuntu或Windows(不推荐)中完成下面任务

1 参考《GMT 0009-2012 SM2密码算法使用规范》第6节“数据转换” 在utils.h和utils.c中完成整数与８位字节串的转换功能(10')：
int Int2ByteArr(unsigned int i, unsigned char * ba);
int ByteArr2Int(unsigned char * ba,unsigned int * i);

2 并写出测试代码测试上述函数(不能与下面代码一样)，比如(10'):
unsigned int i=123456789;
Int2ByteArr(i, ba);
//结果：ba  = {0x07,0x5B,0xCD,0x15};

unsigned char ba [] = {0x07,0x5B,0xCD,0x15};
ByteArr2Int(ba, &i);
//结果： i=123456789

3 提交代码（或代码链接）和运行结果

utils.h

#ifndef UTILS_H
#define UTILS_H
 
int Hex2Char(int fromi,char * toc);
int Char2Hex(char fromc,int * toi);

int Bitstr2ByteArr(unsigned char * bs,unsigned char * ba,int *lba);
int ByteArr2Bitstr(unsigned char * ba,unsigned char * bs,int *lbs);
 
int Int2ByteArr(unsigned int i,unsigned char *ba);
int ByteArr2Int(unsigned char *ba,unsigned int *i);
#endif

utils.c

#include<stdio.h>
#include"utils.h"
#include<string.h>
int Hex2Char(int fromi,char *toc)
{
    if(fromi>=0&&fromi<=9)
    {
        *toc= fromi+'0';
    }
    else if(fromi>=10&&fromi<=15)
    {
        *toc = fromi+'A'-10;
    }
    else
    {
        printf("输入的十六进制数据不正确！");
     }
    return 0;
}
int Char2Hex(char fromc,int *toi)
{
    if(fromc>='0'&& fromc<='9')
    {
             *toi= fromc-'0';
    }
    else if(fromc>='A'&& fromc<='F')
    {
             *toi= fromc-'A'+10;
   
        }
        else
        {
            printf("输入的十六进制字符不正确");
        }
    return 0;
}

int INT2ByteArr(int i,char *ba)
{
   int j;
   int a;
   int sum=0;
   int k=i;
   for(j=0;;j++)
   {
     k=k/16;
     if(k!=0)
      sum++;
     else
       break;
   }
   for(j=sum;j>=0;j--){
     a = i%16;
     Hex2Char(a,&ba[j]);
     i=i/16;   

   }
   ba[sum+1]='\0';


}
int ByteArr2INT(char *ba,int *i)
{
   int len;
   int j;
   int n=0;
   *i=0;
   len = strlen(ba);
   for(j=0;j<len;j++)
   {
      Char2Hex(ba[j],&n);
      //printf("%d\n",n);
      *i=(*i)*16+n; 

   }
   
}

main.c

#include<stdio.h>
#include"utils.h"
int main(){
  //把整型数字转化为字节数组
  int p;
  char bytearr[100];
  printf("Please input an integer\n");
  scanf("%d",&p);
  printf("integer to ByteArr\n");
  INT2ByteArr(p,bytearr);
  printf("ByteArr is: %s\n",bytearr);
 
  //把字节数组转化为整型数字
 
  char barr[100];
  int h;
  printf("Please input ByteArr:");
  scanf("%s",barr);
  printf("ByteArr to integer:");
  ByteArr2INT(barr,&h);
  printf("integer is: %d\n",h);
   
}

运行结果