数据转换-位串字节数组

任务详情
0. 在openEuler(推荐)或Ubuntu或Windows(不推荐)中完成下面任务

1 参考《GMT 0009-2012 SM2密码算法使用规范》第6节“数据转换” 在utils.h和utils.c中完成位串与８位字节串的转换功能(10')：
int Bitstr2ByteArr(unsigned char * bs, unsigned char * ba，int *lba);
int ByteArr2Bitstr(unsigned char * ba, unsigned char * bs, int *lbs);

2 并写出测试代码测试上述函数(不能与下面代码一样)，比如(10'):

unsigned char bs [] = "1010010100011100";
int len;
Bitstr2ByteArr(bs, char * ba, &len);
//结果：ba = {0x5, 0x1C}; len=2

char ba[] = {0x5, 0x1C}
ByteArr2Bitstr(char * ba, char * bs);
//结果：bs= "1010010100011100"
3 提交代码（或代码链接）和运行结果

utils.h

#ifndef UTILS_H
#define UTILS_H
 
int Hex2Char(int fromi,char * toc);
int Char2Hex(char fromc,int * toi);

int Bitstr2ByteArr(unsigned char * bs,unsigned char * ba,int *lba);
int ByteArr2Bitstr(unsigned char * ba,unsigned char * bs,int *lbs);
 
#endif

utils.c

#include<stdio.h>
#include<string.h>
#include"utils.h"

int Hex2Char(int fromi,char *toc)
{
    if(fromi>=0&&fromi<=9)
    {
     *toc= fromi+'0';
    } 
    else if(fromi>=10&&fromi<=15)
    {
     *toc = fromi+'A'-10;
    }
    else
    {
        printf("不在范围内!");
    }
    return 0;
}

int Char2Hex(char fromc,int *toi)
{
 if(fromc>='0'&& fromc<='9')
 {
             *toi= fromc-'0';
 }
 else if(fromc>='A'&& fromc<='F')
 {
             *toi= fromc-'A'+10;
 
        }
        else{
             printf("不在范围内");
        }
 return 0;
}

int ByteArr2Bitstr(unsigned char *ba,unsigned char *bs,int *lba)
{
    int i,j,L,k,a;
    *lba = strlen(ba);
    L = *lba;
    for(j=0;j<L;j++)
    {
        Char2Hex(ba[j],&a);
        for(i=0;i<4;i++)
        {
            bs[3*(j+1)-i+j] = a%2+'0';
            a=a/2;
        }
    }
    bs[4*L]='\0';
}

int Bitstr2ByteArr(unsigned char *bs,unsigned char *ba,int *lbs)
{
   int i,k,j,L;
   *lbs = strlen(bs);
   L = *lbs;
   char string[100];int sum=0;
   if(L%4==1)
   {
     strcpy(string,"000");
     strcat(string,bs);
     k=L/4+1;
   }
   else if(L%4==2)
   {
     strcpy(string,"00");
     strcat(string,bs);
     k=L/4+1;
   }
    else if(L%4==3)
   {
      strcpy(string,"0");;
      strcat(string,bs);
      k=L/4+1;
   }
   else
   {
       k=L/4;
       strcpy(string,bs);
   }
   for(i=0;i<k;i++)
   {
       for(j=0;j<4;j++)
       {
           sum=sum*2;
           sum=sum+(string[4*i+j]-'0');
       }
       Hex2Char(sum,&ba[i]);
       sum=0;
   }
   ba[i]='\0';
}

main.c

#include<stdio.h>
#include"utils.h"
int main(){
  char ba[100];
  char bs[100];
  int *lbs;
  printf("input ByteArr:\n");
  scanf("%s",ba);
  ByteArr2Bitstr(ba,bs,lbs);
  printf("bitstr:\n");
  printf("%s\n",bs);
 
  char ba1[100];
  char bs1[100];
  int *lba;
  printf("input bitstr:\n");
  scanf("%s",bs1);
  Bitstr2ByteArr(bs1,ba1,lba);
  printf("ByteArr:\n");
  printf("%s\n",ba1);
  return 0;
}

运行结果