P2617 Dynamic Rankings

 

P2617 Dynamic Rankings

链接

分析：

　　整体二分！

 

代码

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 typedef long long LL;
 4 
 5 inline int read() {
 6     int x=0,f=1;char ch=getchar();for(;!isdigit(ch);ch=getchar())if(ch=='-')f=-1;
 7     for (;isdigit(ch);ch=getchar())x=x*10+ch-'0';return x*f;
 8 }
 9 
10 const int N = 10010;
11 struct OPT{
12     int l,r,k,ty,id;
13 }A[N*3],B1[N*3],B2[N*3];
14 int ans[N],last[N],n,m;
15 
16 struct BIT{
17     int sum[N];
18     inline void update(int p,int v) {
19         for (; p<=n; p+=p&(-p)) sum[p] += v;
20     }
21     inline int query(int p) {
22         int ans = 0;
23         for (; p; p-=p&(-p)) ans += sum[p];
24         return ans;
25     }
26 }bit;
27 
28 void solve(int Head,int Tail,int L,int R) {
29     if (Head > Tail) return ;
30     if (L == R) {
31         for (int i=Head; i<=Tail; ++i) 
32             if (A[i].ty == 2) ans[A[i].id] = L;
33         return; 
34     }
35     int M = (L + R) >> 1,p1 = 0,p2 = 0;
36     for (int i=Head; i<=Tail; ++i) {
37         if (A[i].ty <= 1) {
38             if (A[i].k <= M) {B1[++p1] = A[i];bit.update(A[i].l,A[i].ty?-1:1);}
39             else B2[++p2] = A[i];
40         }
41         else {
42             int tmp = bit.query(A[i].r)-bit.query(A[i].l-1);
43             if (tmp >= A[i].k) B1[++p1] = A[i];
44             else A[i].k -= tmp,B2[++p2] = A[i];
45         }
46     }
47     for (int i=Head; i<=Tail; ++i) 
48         if (A[i].ty <= 1 && A[i].k <= M) bit.update(A[i].l,A[i].ty?1:-1);
49     for (int i=1; i<=p1; ++i) A[Head+i-1] = B1[i];
50     for (int i=1; i<=p2; ++i) A[Head+p1+i-1] = B2[i];
51     solve(Head,Head+p1-1,L,M);
52     solve(Head+p1,Tail,M+1,R);
53 }
54 
55 int main() {
56     n = read(),m = read();
57     int QueIndex = 0,Idx = 0,Mx = 0,Mn = 1e9;
58     for (int i=1; i<=n; ++i) {
59         int x = read();
60         A[++Idx] = (OPT){i,i,x,0,0};
61         last[i] = x; 
62         Mx = max(Mx,x);Mn = min(Mn,x);
63     }
64     char opt[5];
65     for (int i=1; i<=m; ++i) {
66         scanf("%s",opt);
67         if (opt[0] == 'Q') {
68             int a = read(),b = read(),c = read();
69             A[++Idx] = (OPT){a,b,c,2,++QueIndex};
70         }
71         else {
72             int p = read(),x = read();
73             A[++Idx] = (OPT){p,p,last[p],1,0};
74             A[++Idx] = (OPT){p,p,last[p]=x,0,0};
75             Mx = max(Mx,x);Mn = min(Mn,x);
76         }
77     }
78     solve(1,Idx,Mn,Mx);
79     for (int i=1; i<=QueIndex; ++i) printf("%d\n",ans[i]);
80     return 0;
81 }

 

posted @ 2018-06-27 21:30  MJT12044  阅读(238)  评论(0)  编辑  收藏  举报