动态规划-最长公共子序列

 

 

#include <iostream>
using namespace std;

const int N = 1010;

int n, m;
char a[N], b[N];
int f[N][N];

int main()
{
    cin >> n >> m;
    cin >> a + 1 >> b + 1;
    
    for (int i = 1; i <= n; ++ i)
    {
        for (int j = 1; j <= m; ++ j)
        {
            f[i][j] = max(f[i - 1][j], f[i][j - 1]);
            if (a[i] == b[j])   f[i][j] = max(f[i][j], f[i - 1][j - 1] + 1);
        }
    }    
    
    cout << f[n][m] << endl;
    
    return 0;
}

 

posted @ 2021-08-29 20:03  青衫客36  阅读(16)  评论(0编辑  收藏  举报