poj 2039 To and Fro

#include <iostream>
#include
<string>
using namespace std;
int main()
{
int interval,row,i,j;
char str[210];
while(cin>>interval&&interval)
{
cin
>>str;
row
=strlen(str)/interval;
for(i=0;i<interval;i++)
for(j=0;j<row;j++)
{
if(j%2==0)
cout
<<str[interval*j+i];
else
cout
<<str[interval*(j+1)-1-i];
}
cout
<<endl;
}
return 0;
}

  

posted on 2011-07-18 11:33  sysu_mjc  阅读(112)  评论(0编辑  收藏  举报

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