Markdown 语法

markdown语法

1 公式

1.1 行间

1.1.1 对齐

使用 \begin{align}\end{align} 可实现公式的对齐

\begin{align}
\frac{1}{a} \sum^{n}_{k=1} =1+2+ \cdots + n \\
 \prod_\epsilon =3 \\
\int_0 -2-4-\cdots-(2n-2)
 = 3\end{align}

\[\begin{align} \frac{1}{a} \sum^{n}_{k=1} =1+2+ \cdots + n\\ \prod _\epsilon =3\\ \int_0 -2-4-\cdots-(2n-2) = 3\end{align} \]

默认右对齐,可以在想对齐的位置加上 & (注意, & 在左在右有区别)

\begin{align}
\frac{1}{a} \sum^{n}_{k=1} &=1+2+ \cdots + n\\
\prod _\epsilon &=3\\
\int_0 -2-\cdots-(2n-2)
 &= 3\end{align}

\[\begin{align} \frac{1}{a} \sum^{n}_{k=1} &=1+2+ \cdots + n\\ \prod _\epsilon &=3\\ \int_0 -2-\cdots-(2n-2) &= 3\end{align} \]

align 改为 aligned 可以去掉自动的编号

\begin{aligned}
\frac{1}{a} \sum^{n}_{k=1} &=1+2+ \cdots + n\\
\prod _\epsilon &=3\\
\int_0 -2-\cdots-(2n-2)
 &= 3\end{aligned}

\[\begin{aligned} \frac{1}{a} \sum^{n}_{k=1} &=1+2+ \cdots + n\\ \prod _\epsilon &=3\\ \int_0 -2-\cdots-(2n-2) &= 3\end{aligned} \]

1.1.2 大括号(只使用2.)

f(x)=\left\{
\begin{aligned}
x & = & \cos(t) \\
y & = & \sin(t) \\
z & = & \frac xy
\end{aligned}
\right.

\[f(x) = \left \{ \begin{aligned} x & = & \cos(t) \\ y & = & \sin(t) \\ z & = & \frac xy \end{aligned} \right. \]

F^{HLLC}=\left\{
\begin{array}{rcl}
F_Ladasd       &      & {0      <      S_L}\\
F^*_L     &      & {S_L \leq 0 < S_M}\\
F^*_R     &      & {S_M \leq 0 < S_R}\\
F_R       &      & {S_R \leq 0}
\end{array} \right. 

这里rcl指第一栏右对齐,第二栏中心对齐,第三栏左对齐。参数可以不写,默认中心对齐,但是必须得有大括号
加一个 & 分隔出两栏。

\[F^{HLLC}=\left\{ \begin{array}{rcl} F_Ladasd & & {0 < S_L}\\ F^*_L & & {S_L \leq 0 < S_M}\\ F^*_R & & {S_M \leq 0 < S_R}\\ F_R & & {S_R \leq 0} \end{array} \right. \]

f(x)=
\begin{cases}
0& \text{x=0}\\
1& \text{x!=0}
\end{cases}

\[f(x)= \begin{cases} 0& \text{x=0}\\ 1& \text{x!=0} \end{cases} \]

\[f(x)= \left\{ \begin{array}{l} 0& \textrm{x=0}\\ 1& \textrm{x$\ne$0} \end{array} \right. \]

1.1.3 行列式与矩阵的表示

\begin{gathered}
\begin{matrix} 0 & 1 \\ 1 & 0 \end{matrix}
\quad
\begin{pmatrix} 0 & -i \\ i & 0 \end{pmatrix}
\quad
\begin{bmatrix} 0 & -1 \\ 1 & 0 \end{bmatrix}
\quad
\begin{Bmatrix} 1 & 0 \\ 0 & -1 \end{Bmatrix}
\quad
\begin{vmatrix} a & b \\ c & d \end{vmatrix}
\quad
\begin{Vmatrix} i & 0 \\ 0 & -i \end{Vmatrix}
\end{gathered}

\[\begin{gathered} \begin{matrix} 0 & 1 \\ 1 & 0 \end{matrix} \quad \begin{pmatrix} 0 & -i \\ i & 0 \end{pmatrix} \quad \begin{bmatrix} 0 & -1 \\ 1 & 0 \end{bmatrix} \quad \begin{Bmatrix} 1 & 0 \\ 0 & -1 \end{Bmatrix} \quad \begin{vmatrix} a & b \\ c & d \end{vmatrix} \quad \begin{Vmatrix} i & 0 \\ 0 & -i \end{Vmatrix} \end{gathered} \]

posted @ 2021-10-30 14:29  砥安  阅读(154)  评论(0编辑  收藏  举报