List之Distinct()
针对数组可以用List.Distinct(),可以过滤掉重复的内容。
针对对象中的某个字段只能用Distinct(IEqualityComparer<T>)
用法:
1 public class AppIndex:BasePage
2 {
3 public void DoGet()
4 {
5 List<test11> list_test = new List<test11>();
6 list_test.Add(new test11() {
7 m=1,
8 v="one"
9 });
10 list_test.Add(new test11()
11 {
12 m = 2,
13 v = "two"
14 });
15 list_test.Add(new test11()
16 {
17 m = 3,
18 v = "three"
19 });
20 list_test.Add(new test11()
21 {
22 m = 4,
23 v = "fornt"
24 });
25 list_test.Add(new test11()
26 {
27 m = 4,
28 v = "fornt"
29 });
30 list_test.Add(new test11()
31 {
32 m = 3,
33 v = "fornt"
34 });
35 var ss = list_test.Distinct(new Comparint());//这里调用
36 this.Add("mylist",new Travel.DAL.AppActive().GetList(BaseCode));
37 }
38 }
39
40 public class test11
41 {
42 public int m { get; set; }
43 public string v { get; set; }
44 }
45 public class Comparint : IEqualityComparer<test11>
46 {
47
48 public bool Equals(test11 x, test11 y)
49 {
50 if (x == null && y == null)
51 return false;
52 return x.m==y.m;
53 }
54
55 public int GetHashCode(test11 obj) {
56 return obj.ToString().GetHashCode();
57 }
58 }
同样table 也可以用这个方法。只要一步ASEnumerable()即可
var _comPresult = _dt.AsEnumerable().Distinct(new DataTableRowCompare());
DataTable _resultDt = _comPresult.CopyToDataTable();
_resultDt.AsEnumerable().ToList().ForEach(
x =>
{
Console.WriteLine(x["id"].ToString() + " " + x["name"].ToString() + " " + x["address"].ToString());
});
public class DataTableRowCompare : IEqualityComparer<DataRow>
{
#region IEqualityComparer<DataRow> 成员
public bool Equals(DataRow x, DataRow y)
{
return (x.Field<int>("id") == y.Field<int>("id")); 这个是根据自己的需求写比较字段的
}
public int GetHashCode(DataRow obj)
{
return obj.ToString().GetHashCode();
}
#endregion
}
业精于勤荒于嬉 行成于思毁于随