剑指offer 链表中倒数第k个节点
本内容为牛客网,剑指off题目:链表中倒数第k个节点
# -*- coding: utf-8 -*- """ Created on Tue Mar 12 21:21:40 2019 @author: Administrator 输入一个链表,输出该链表中倒数第k个结点。 本解法没有考虑到k的值超过了链表的最大长度 """ class ListNode: def __init__(self,x): self.val = x self.next = None class Solution: def FindKthToTail(self,head,k): first,second = head,head #定义两个地址分别存放间距为k的节点地址 for i in range(k): #先从头指到第k个节点位置 second = second.next while second: #两个节点依次运行,直到尾节点结束 first = first.next second = second.next return first if __name__ == '__main__': n = ListNode(1) n2 = ListNode(2) n3 = ListNode(3) n4 = ListNode(4) n5 = ListNode(5) n4.next = n5 n3.next = n4 n2.next = n3 n.next = n2 solution = Solution() result = solution.FindKthToTail(n,3) while True: print(result.val) result = result.next if result == None: break