Informix日期获取上周上月昨天去年SQL
遇到同步数据类工作通常需要对日期进行转换，记录一下Informix SQL遇到的写法。
标准sql语法和Informix SQL 函数可百度了解.
1、准备测试表
由于Informix没有dual表，我们新建test_tab，并插入一条数据作为测试表。
- 建表
--建表
create table test_tab(
testId int,
insert_time datetime year to second default current year to second --插入时间 默认当前时间
);
--插入一条数据
insert into test_tab(testId) values(1);
- 查看测试表
--查询测试表
select * from test_tab;
| testId | insert_time |
|---|---|
| 1 | 2018-11-28 16:31:18 |
2、日期转换
- 转换日期为指定字符串格式，如yyyy-MM-dd HH:mm:ss格式：
select testid, to_char(today, '%Y-%m-%d %H:%M:%S') as cur_time
from test_tab;
| testId | cur_time |
|---|---|
| 1 | 2018-11-28 00:00:00 |
today 指今天 yyyy-MM-dd
- 转换字符串为日期格式，如字符串 '2018/11/28 16:31:18'
select testid, to_date('2018/11/28 16:31:18', '%Y/%m/%d %H:%M:%S') as cur_time
from test_tab;
| testId | cur_time |
|---|---|
| 1 | 2018-11-28 16:31:18 |
3、获取上个小时，昨天和上个月
理解了相关函数，实现方式非常多，接下来会举一些例子。
- 昨天
select testid, today - 1 as yeaterday
,sysdate - 1 units day as yeaterday_t
from test_tab;
| testId | yeaterday | yeaterday_t |
|---|---|---|
| 1 | 2018-11-27 | 2018-11-27 16:31:18 |
sysdate 指当前时间 yyyy-MM-dd HH:mm:ss
当前时间减去一天即为昨天此时
- 上个小时
select testid
,sysdate-1 units hour lasthour
,sysdate - interval(1) hour to hour lasthour1
,extend(sysdate-1 units hour,year to hour) lasthour2
from test_tab;
| testId | lasthour | lasthour1 | lasthour2 |
|---|---|---|---|
| 1 | 2018-11-28 16:29:03 | 2018-11-28 16:29:03 | 2018-11-28 16:00:00 |
extend 可以把日期处理成想要的精度
- 上周日期
select testid,today as cur_date
,to_char(today,'%A') as weekstr
,weekday(today) as wday
,today -weekday(today) as lastsunday
,today -weekday(today)-6 as lastmonday
from test_tab;
| testId | cur_date | weekstr | wday | lastsunday | lastmonday |
|---|---|---|---|---|---|
| 1 | 2018-11-28 | Wednesday | 3 | 2018-11-25 | 2018-11-19 |
weekday(today) 显示当前是周的第几天，可以理解为 dayOfWeek
day(today)则可表示dayOfMonth
- 上月日期
select testid,today as cur_date
,to_char(sysdate-1 units month,'%Y%m') as lastmon_str
,day(today) as dday
,today -day(today) as lastmon_end
,to_date(to_char(sysdate-1 units month,'%Y%m')|| '01', '%Y%m%d') as lastmon_begin
,extend(sysdate - 1 units month,year to month) as lastmon_begin1
from test_tab;
| testId | cur_date | lastmon_str | dday | lastmon_end | lastmon_begin | lastmon_begin1 |
|---|---|---|---|---|---|---|
| 1 | 2018-11-28 | 201810 | 28 | 2018-10-31 | 2018-10-01 00:00:00 | 2018-10-01 00:00:00 |
select testid,today as cur_date
,mdy(month(today),1,year(today)) thismonth
,mdy(month(today)-1,1,year(today)) lastmon_begin
,mdy(month(today),1,year(today))-1 units day lastmon_end
from test_tab
| testId | cur_date | thismonth | lastmon_begin | lastmon_end |
|---|---|---|---|---|
| 1 | 2018-11-28 | 2018-11-01 | 2018-10-01 | 2018-10-31 00:00:00 |
informix里字符串拼接使用 "||"
mdy(m,d,y)
