摘要: TASK 4 点击查看代码 #include <stdio.h> int main() { int count = 0; int ch; FILE *fp; fp = fopen("data4.txt", "r"); if (fp == NULL) { printf("fail to open fi 阅读全文
posted @ 2024-06-24 12:55 MINXZBC 阅读(8) 评论(0) 推荐(0) 编辑