1.闭包
2.JS操作和获取cookie
//创建cookie function setCookie(name, value, expires, path, domain, secure) { var cookieText = encodeURIComponent(name) + '=' + encodeURIComponent(value); if (expires instanceof Date) { cookieText += '; expires=' + expires; } if (path) { cookieText += '; expires=' + expires; } if (domain) { cookieText += '; domain=' + domain; } if (secure) { cookieText += '; secure'; } document.cookie = cookieText; } //获取cookie function getCookie(name) { var cookieName = encodeURIComponent(name) + '='; var cookieStart = document.cookie.indexOf(cookieName); var cookieValue = null; if (cookieStart > -1) { var cookieEnd = document.cookie.indexOf(';', cookieStart); if (cookieEnd == -1) { cookieEnd = document.cookie.length; }
3.js数组去重
function arr1() { var n = []; //一个新的临时数组 for (var i = 0; i < this.length; i++) //遍历当前数组 { //如果当前数组的第i已经保存进了临时数组,那么跳过, //否则把当前项push到临时数组里面 if (n.indexOf(this[i]) == -1) n.push(this[i]); } return n; } function arr2(){ var n = {},r=[]; //n为hash表,r为临时数组 for(var i = 0; i < this.length; i++) //遍历当前数组 { if (!n[this[i]]) //如果hash表中没有当前项 { n[this[i]] = true; //存入hash表 r.push(this[i]); //把当前数组的当前项push到临时数组里面 } } return r; } function arr3(){ var n = [this[0]]; //结果数组 for(var i = 1; i < this.length; i++) //从第二项开始遍历 { //如果当前数组的第i项在当前数组中第一次出现的位置不是i, //那么表示第i项是重复的,忽略掉。否则存入结果数组 if (this.indexOf(this[i]) == i) n.push(this[i]); } return n; }
4.
原创笔记