JUC-线程间通信

面试题:

两个线程,一个线程打印1-52,另一个打印字母A-Z打印顺序为12A34B...5152Z, 

要求用线程间通信

线程间通信:1、生产者+消费者2、通知等待唤醒机制

多线程编程模版中

1、判断

2、干活

3、唤醒

 

synchronized实现

package com.atguigu.thread;
 
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;
 
import org.omg.IOP.Codec;
 
 
class ShareDataOne//资源类
{
  private int number = 0;//初始值为零的一个变量
 
  public synchronized void increment() throws InterruptedException 
  {
     //1判断
     if(number !=0 ) {
       this.wait();
     }
     //2干活
     ++number;
     System.out.println(Thread.currentThread().getName()+"\t"+number);
     //3通知
     this.notifyAll();
  }
  
  public synchronized void decrement() throws InterruptedException 
  {
     // 1判断
     if (number == 0) {
       this.wait();
     }
     // 2干活
     --number;
     System.out.println(Thread.currentThread().getName() + "\t" + number);
     // 3通知
     this.notifyAll();
  }
}
 
/**
 * 
 * @Description:
 *现在两个线程,
 * 可以操作初始值为零的一个变量,
 * 实现一个线程对该变量加1,一个线程对该变量减1,
 * 交替,来10轮。 
 * @author xialei
 *
 *  * 笔记:Java里面如何进行工程级别的多线程编写
 * 1 多线程变成模板(套路)-----上
 *     1.1  线程    操作    资源类  
 *     1.2  高内聚  低耦合
 * 2 多线程变成模板(套路)-----下
 *     2.1  判断
 *     2.2  干活
 *     2.3  通知
 
 */
public class NotifyWaitDemoOne
{
  public static void main(String[] args)
  {
     ShareDataOne sd = new ShareDataOne();
     new Thread(() -> {
       for (int i = 1; i < 10; i++) {
          try {
            sd.increment();
          } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
          }
       }
     }, "A").start();
     new Thread(() -> {
       for (int i = 1; i < 10; i++) {
          try {
            sd.decrement();
          } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
          }
       }
     }, "B").start();
  }
}
/*
 * * 
 * 2 多线程变成模板(套路)-----下
 *     2.1  判断
 *     2.2  干活
 *     2.3  通知
 * 3 防止虚假唤醒用while
 * 
 * 
 * */
 

换成4个线程会导致错误,虚假唤醒 

  

原因:在java多线程判断时,不能用if,程序出事出在了判断上面, 

突然有一添加的线程进到if了,突然中断了交出控制权, 

没有进行验证,而是直接走下去了,加了两次,甚至多次

 

解决虚假唤醒:查看API,java.lang.Object 

mmnotes://1.png

中断和虚假唤醒是可能产生的,所以要用loop循环,if只判断一次,while是只要唤醒就要拉回来再判断一次。if换成while

java8实现

mmnotes://0.png

Condition:查看API,java.util.concurrent 
 
 
class BoundedBuffer {
   final Lock lock = new ReentrantLock();
   final Condition notFull  = lock.newCondition(); 
   final Condition notEmpty = lock.newCondition(); 


   final Object[] items = new Object[100];
   int putptr, takeptr, count;


   public void put(Object x) throws InterruptedException {
     lock.lock();
     try {
       while (count == items.length)
         notFull.await();
       items[putptr] = x;
       if (++putptr == items.length) putptr = 0;
       ++count;
       notEmpty.signal();
     } finally {
       lock.unlock();
     }
   }
 

mmnotes://0.png

 线程间定制化调用通信

 

package com.atguigu.thread;


import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;




class ShareResource
{
  private int number = 1;//1:A 2:B 3:C 
  private Lock lock = new ReentrantLock();
  private Condition c1 = lock.newCondition();
  private Condition c2 = lock.newCondition();
  private Condition c3 = lock.newCondition();


  public void print5(int totalLoopNumber)
  {
     lock.lock();
     try 
     {
       //1 判断
       while(number != 1)
       {
          //A 就要停止
          c1.await();
       }
       //2 干活
       for (int i = 1; i <=5; i++) 
       {
          System.out.println(Thread.currentThread().getName()+"\t"+i+"\t totalLoopNumber: "+totalLoopNumber);
       }
       //3 通知
       number = 2;
       c2.signal();
     } catch (Exception e) {
       e.printStackTrace();
     } finally {
       lock.unlock();
     }
  }
  public void print10(int totalLoopNumber)
  {
     lock.lock();
     try 
     {
       //1 判断
       while(number != 2)
       {
          //A 就要停止
          c2.await();
       }
       //2 干活
       for (int i = 1; i <=10; i++) 
       {
          System.out.println(Thread.currentThread().getName()+"\t"+i+"\t totalLoopNumber: "+totalLoopNumber);
       }
       //3 通知
       number = 3;
       c3.signal();
     } catch (Exception e) {
       e.printStackTrace();
     } finally {
       lock.unlock();
     }
  }  
  
  public void print15(int totalLoopNumber)
  {
     lock.lock();
     try 
     {
       //1 判断
       while(number != 3)
       {
          //A 就要停止
          c3.await();
       }
       //2 干活
       for (int i = 1; i <=15; i++) 
       {
          System.out.println(Thread.currentThread().getName()+"\t"+i+"\t totalLoopNumber: "+totalLoopNumber);
       }
       //3 通知
       number = 1;
       c1.signal();
     } catch (Exception e) {
       e.printStackTrace();
     } finally {
       lock.unlock();
     }
  }  
}




/**
 * 
 * @Description: 
 * 多线程之间按顺序调用,实现A->B->C
 * 三个线程启动,要求如下:
 * 
 * AA打印5次,BB打印10次,CC打印15次
 * 接着
 * AA打印5次,BB打印10次,CC打印15次
 * ......来10轮  
 * @author xialei
 *
 */
public class ThreadOrderAccess
{
  public static void main(String[] args)
  {
     ShareResource sr = new ShareResource();
     
     new Thread(() -> {
       for (int i = 1; i <=10; i++) 
       {
          sr.print5(i);
       }
     }, "AA").start();
     new Thread(() -> {
       for (int i = 1; i <=10; i++) 
       {
          sr.print10(i);
       }
     }, "BB").start();
     new Thread(() -> {
       for (int i = 1; i <=10; i++) 
       {
          sr.print15(i);
       }
     }, "CC").start();   
     
     
  }
}



 

posted @ 2019-08-26 15:04  keepsummer  阅读(305)  评论(0编辑  收藏  举报