使用最常用的方法,判断从1到sqrt(n)的数,看是否i%这个数为0,为0,则不是素数...
Code
#include <stdlib.h>
#include <iostream.h>
#include <math.h>
inline long sqrt(long i)
{
long r,rnew=1,rold=r;
do
{
rold=r;
r=rnew;
rnew = (r+(i/r));
rnew >>= 1;
}
while(rold != rnew);
return rnew;
}
inline int isprime(long i)
{
long si,j;
si = sqrt(i);
for (j=2; (j<=si); j++)
{
if (i%j == 0)
return 0;
}
return 1;
}
void main(int argc, char *argv[])
{
long i,i1,i2,f=0;
if (argc < 2)
{
cout << endl << endl;
cout << "Prime number finder: Hugo Elias 1998" << endl << "http://freespace.virgin.net/hugo.elias" << endl << endl;
cout << "Usage:" << endl << " primes a b > primes.txt" << endl << endl;
cout << "will find all primes between a and b" << endl << "and will write the results to the file PRIMES.TXT" << endl;
return;
}
i1 = atol(argv[1]);
i2 = atol(argv[2]);
for (i=i1; i<i2; i++)
if (isprime(i))
{
f++;
if (f==16)
{
cout << endl;
f=0;
}
cout << i << " ";
}
}