python二进制读写及特殊码同步

python对二进制文件的操作需要使用bytes类，直接写入整数是不行的，如果试图使用f.write(123)向文件中以二进制写入123，结果提示参数不是bytes类型。

 

import os
import struct

a = 0x1A2B3C4D
b = 0x239875ad3d5ffaaa

filepath = 'D:\\wygDocument\\python\\code\\abc.dat'
f_in = open(filepath,'wb+')

for value in range(1,5):
  f_in.write(struct.pack('>I',a))
  f_in.write(struct.pack('>Q',b))
  
f_in.close()
print('Write OK')

 

import os
import struct

#Read file into list
with open('E:/fep/tj19.txt','r') as f:
  line = f.read().strip()
  linestr = line.split('\n')  #splited by line breaks
  #linestr = line.split(r"[\s\n]",line)  #splited by Space character and line breaks

f_out = open('E:/fep/realData.dat','xb')

frame_flag_0 = 0x1A2B3C4D5E6F
mask = 0xFFFFFFFFFFFF

for i in range(0,len(linestr)):
  filepath = 'E:/fep/19/' + linestr[i]
  f_in = open(filepath,'rb')
  f_size = os.path.getsize(filepath)
  f_in.seek(109)

  offset = 109
  chunk = 905
  
  while True:
    if offset >= f_size:
      break
    buff = f_in.read(15)
    offset += chunk

    unpacked_data = struct.unpack_from('>ih',buff,9)  #start from the 9th byte
    if(unpacked_data[0] != 439041101) or (unpacked_data[1] != 24175)  #1A2B3C4D     5E6F
      f_out.write(buff)
      f_out.write(f_in.read(890))  # 9 + 6 + 890

    f_in.seek(offset)

  f_in.close()
  f_out.flush()

f_out.close()
print('OK')