Newtonsoft.Json

C# JsonConvert时间格式问题

var format = new IsoDateTimeConverter();
format.DateTimeFormat = "yyyy-MM-dd hh:mm:ss";

string param = JsonConvert.SerializeObject(data, format);

C# Newtonsoft.Json不序列字段

[JsonObject(MemberSerialization.OptOut)]
public class employeePersonalForm {
        [JsonIgnore]
        public string id { get; set; }
}

 

{
"Category": {
		"Better": [ 99, 98, 100, 96 ],
		"Normal": [ 80, 75, 84 ]
	}
}

 提取数组:

Newtonsoft.Json.Linq.JObject obj= (JObject)JsonConvert.DeserializeObject(jsonText);

var arr = obj["Category"]["Better"] as JArray;  

Newtonsoft.Json.Linq.JToken tobj = obj.First;

var Path = tobj.Path;  //Category

var arr = obj[Path].First as JArray;

 

var Name= obj.Name;  //Category

 

posted @ 2022-04-19 12:05  microsoft-zhcn  阅读(37)  评论(0编辑  收藏  举报