.NET List常见操作之交集并集差集(转)

一、简单类型List的交集并集差集

1、先定义两个简单类型的List

List<int> listA = new List<int>() { 1, 2, 3, 4, 5, 6, 7, 8 };
List<int> listB = new List<int>() { 1, 2, 3, 4, 9 };

 

2、取两个List的并集

var resultUnionList= listA.Union(listB).ToList();

执行结果如下:

  

3、取两个List的交集

var resultIntersectList = listA.Intersect(listB);

执行结果如下:

  

4、取两个List的差集,差集是指取在该集合中而不在另一集合中的所有的项

var resultExceptList = listA.Except(listB);

执行结果如下:

  

二、对象List集合的交集并集差集

1、先定义一个类

    /// <summary>
    /// 学生类
    /// </summary>
    public class Student
    {
        public string Name { get; set; }
        public int Age { get; set; }
        public string Sex { get; set; }
    }

2、定义两个List

            //LISTA
            List<Student> stuListA = new List<Student>();
            stuListA.Add(new Student
            {
                Name = "A1",
                Age = 10,
                Sex = "男"
            });
            stuListA.Add(new Student
            {
                Name = "A2",
                Age = 11,
                Sex = "男"
            });

            //LISTB
            List<Student> stuListB = new List<Student>();
            stuListB.Add(new Student
            {
                Name = "B1",
                Age = 10,
                Sex = "女"
            });
            stuListB.Add(new Student
            {
                Name = "B2",
                Age = 11,
                Sex = "男"
            });   

 

3、取上述两个list集合的并集

var result = stuListA.Union(stuListB).ToList();

 

4、取上述两个list集合的交集,应为是对象集合,可以根据一定规则 Func<TSource, bool> predicate限定那些属于交集

(1)取两个对象集合中对象名称一样的交集

var result = stuListA.Where(x => stuListB.Any(e => e.Name == x.Name)).ToList();

  

(2)取两个对象集合中对象名称、对象年龄、对象性别都一样的交集

var result = stuListA.Where(x => stuListB.Any(e => e.Name == x.Name && e.Age == x.Age && e.Sex == x.Sex)).ToList();

 

5、取上述两个list集合的差集,可以根据一定规则 Func<TSource, bool> predicate限定那些属于差集

(1)取差集,根据两个对象集合中对象名称一样的规则取差集

var result = stuListA.Where(x =>! stuListB.Any(e => e.Name == x.Name)).ToList();

  

(2)取差集,根据两个对象集合中对象名称、对象年龄、对象性别都一样的规则取差集

var result = stuListA.Where(x => !stuListB.Any(e => e.Name == x.Name && e.Age == x.Age && e.Sex == x.Sex)).ToList();

三、List<string>和List<int>互相转换

List<string> 转 List<int>

var list = (new[]{"1","2","3"}).ToList();
var newlist = list.Select<string,int>(x =>Convert.ToInt32(x));

List<int> 转List<string> 

List<int> list = new List<int>(new int[] { 1,2,3 } );
List<string> newList = list.ConvertAll<string>(x => x.ToString());

四、List排重

1、使用linq提供的Distinct方法

public class Test
{ 
     public int ID { get; set; }
     public string Name { get; set; }
}
public class TestMain
{
  public static void TestMothod()
  {
     List<Test> testList = new List<Test>();
      testList.Add(new Test { ID = 1, Name = "小名" });
      testList.Add(new Test { ID = 1, Name = "小红" });
      testList.Add(new Test { ID = 2, Name = "小名" });
      //通过使用默认的相等比较器对值进行比较返回序列中的非重复元素。
      List<Test> tempList = testList.Distinct<Test>().ToList();
   }
}

2、根据某个字段排除重复项

添加一个扩展排重扩展方法:

 public static class DistinctExtension
 {
    public static IEnumerable<TSource> DistinctBy<TSource, TKey>(this IEnumerable<TSource> source, System.Func<TSource, TKey> keySelector)
    {
        HashSet<TKey> seenKeys = new HashSet<TKey>();
        foreach (TSource element in source)
        {
            if (seenKeys.Add(keySelector(element)))
            {
                yield return element;
            }
        }
    }
 }

使用上述扩展方法:

public class TestMain
{
  public static void TestMothod()
   {
       List<Test> testList = new List<Test>();
       testList.Add(new Test { ID = 1, Name = "小名" });
       testList.Add(new Test { ID = 1, Name = "小红" });
       testList.Add(new Test { ID = 2, Name = "小名" });
       //根据某个字段排除重复项。
       List<Test> tempList = testList.DistinctBy(p => p.ID).ToList();
   }
}
 
posted @ 2022-10-25 13:15  microsoft_xin  阅读(1083)  评论(0编辑  收藏  举报