摘要: List<string> names = new List<string>() { "a00", "b00", "c00", "d00" }; dynamic obj = new DynObj(); obj.date = "2019-02-26"; obj.stories = names; stri 阅读全文
posted @ 2019-08-19 14:46 白羽轻飘 阅读(1552) 评论(1) 推荐(0) 编辑