08 2014 档案

http GET
摘要：向php脚本中传参数可以用http GET 方法，比如要向file.php传两个参数v1和v2.则可以这么做file.php?v1=1&v2=2(一个链接而已，直接编辑URL即可传参数了)这样在file.php中要获得v1和v2的值，可以这么做：$v1= $_GET['v1'];$v2= $_GET... 阅读全文
posted @ 2014-08-31 17:04 zmiao 阅读(172) 评论(0) 推荐(0) 编辑
free web visitor counter
摘要：http://www.simplehitcounter.com/ 阅读全文
posted @ 2014-08-30 17:50 zmiao 阅读(107) 评论(0) 推荐(0) 编辑
contact form
摘要：use the existing service:http://www.foxyform.com/ 阅读全文
posted @ 2014-08-30 12:04 zmiao 阅读(98) 评论(0) 推荐(0) 编辑
override the hashcode and equals method in java
摘要：http://howtodoinjava.com/2012/10/09/working-with-hashcode-and-equals-methods-in-java/ 阅读全文
posted @ 2014-08-29 08:05 zmiao 阅读(92) 评论(0) 推荐(0) 编辑
find the closest sum to a target value
摘要：problem: given an array of integers including positive and negative, a target value. find 2 numbers in the array such that the sum of the 2 numbers is... 阅读全文
posted @ 2014-08-27 03:35 zmiao 阅读(125) 评论(0) 推荐(0) 编辑
dynamic programming
摘要：Dynamic programming, or the "put shit in a table" technique, is an optimization for certain types of recurrence problems (specifically, those with ove... 阅读全文
posted @ 2014-08-26 10:45 zmiao 阅读(130) 评论(0) 推荐(0) 编辑
divide an integer into X parts (as even as possible)
摘要：the algorithm is like this: it evenly spreads an integer N over K cells.for i = 0 to K array[i] = N / K # integer division# divide up the remain... 阅读全文
posted @ 2014-08-26 04:47 zmiao 阅读(155) 评论(0) 推荐(0) 编辑
git入门
摘要：http://hi.baidu.com/eehuang/item/22283e220437a80d76272cb7 阅读全文
posted @ 2014-08-20 13:19 zmiao 阅读(93) 评论(0) 推荐(0) 编辑
regular expression tutorial
摘要：\d represent any number\D represents everything but a number\s represents any space\S Anything but a space\w Any character\W Anything but a character.... 阅读全文
posted @ 2014-08-20 10:04 zmiao 阅读(165) 评论(0) 推荐(0) 编辑
Kth order statistcs
摘要：Selection:selection is a trivial problem if the input numbers are sorted. If we use a sorting algorithm having O(nlgn) worst case running time, then t... 阅读全文
posted @ 2014-08-19 03:44 zmiao 阅读(263) 评论(0) 推荐(0) 编辑
改MAC地址
摘要：Google TMAC v6.Or click here 阅读全文
posted @ 2014-08-18 10:53 zmiao 阅读(111) 评论(0) 推荐(0) 编辑
odd or even?
摘要：public boolean isEven(int data){ if((data&1)== 0) return true; return false; }much faster than using % 阅读全文
posted @ 2014-08-15 05:59 zmiao 阅读(166) 评论(0) 推荐(0) 编辑