OrderedDict

因为项目用的python3.5,字典还是无序的,所以需要把OrderedDict捡一捡。

1.创建有序字典

复制代码
import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
print(dic)

#输出:OrderedDict([('k1', 'v1'), ('k2', 'v2'), ('k3', 'v3')])
复制代码

2.clear(清空有序字典)

复制代码
import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic.clear()
print(dic)

#输出:OrderedDict()
复制代码

3.copy(拷贝)

复制代码
import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
new_dic = dic.copy()
print(new_dic)

#输出:OrderedDict([('k1', 'v1'), ('k2', 'v2')])
#浅拷贝
复制代码

4.fromkeys(指定一个列表,把列表中的值作为字典的key,生成一个字典)

复制代码
import collections

dic = collections.OrderedDict()
name = ['tom','lucy','sam']
print(dic.fromkeys(name))
print(dic.fromkeys(name,20))

#输出:OrderedDict([('tom', None), ('lucy', None), ('sam', None)])
#     OrderedDict([('tom', 20), ('lucy', 20), ('sam', 20)])
复制代码

5.items(返回由“键值对组成元素“的列表)

import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
print(dic.items())

#输出:odict_items([('k1', 'v1'), ('k2', 'v2')])

6.keys(获取字典所有的key)

import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
print(dic.keys())

# 输出:odict_keys(['k1', 'k2'])

7.move_to_end(指定一个key,把对应的key-value移到最后)

复制代码
import collections
import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
dic.move_to_end('k1')
print(dic)

# 输出:OrderedDict([('k2', 'v2'), ('k3', 'v3'), ('k1', 'v1')])
复制代码

8.pop(获取指定key的value,并在字典中删除)

复制代码
import collections
import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
k = dic.pop('k2')
print(k,dic)

# 输出:v2 OrderedDict([('k1', 'v1'), ('k3', 'v3')])
复制代码

9.popitem(按照后进先出原则,删除最后加入的元素,返回key-value)

复制代码
import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
print(dic.popitem(),dic)
print(dic.popitem(),dic)

# 输出:('k3', 'v3') OrderedDict([('k1', 'v1'), ('k2', 'v2')])
#      ('k2', 'v2') OrderedDict([('k1', 'v1')])
复制代码

10.setdefault(获取指定key的value,如果key不存在,则创建)

复制代码
import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
val = dic.setdefault('k5')
print(val,dic)

# 输出:None OrderedDict([('k1', 'v1'), ('k2', 'v2'), ('k3', 'v3'), ('k5', None)])
复制代码

11.values(获取字典所有的value,返回一个列表)

复制代码
import collections

dic = collections.OrderedDict()
dic['k1'] = 'v1'
dic['k2'] = 'v2'
dic['k3'] = 'v3'
print(dic.values())

# 输出:odict_values(['v1', 'v2', 'v3'])
复制代码

 

posted on   不要挡着我晒太阳  阅读(379)  评论(0编辑  收藏  举报

编辑推荐:
· AI与.NET技术实操系列:向量存储与相似性搜索在 .NET 中的实现
· 基于Microsoft.Extensions.AI核心库实现RAG应用
· Linux系列:如何用heaptrack跟踪.NET程序的非托管内存泄露
· 开发者必知的日志记录最佳实践
· SQL Server 2025 AI相关能力初探
阅读排行:
· 震惊!C++程序真的从main开始吗?99%的程序员都答错了
· winform 绘制太阳,地球,月球 运作规律
· 【硬核科普】Trae如何「偷看」你的代码?零基础破解AI编程运行原理
· 上周热点回顾(3.3-3.9)
· 超详细:普通电脑也行Windows部署deepseek R1训练数据并当服务器共享给他人
< 2025年3月 >
23 24 25 26 27 28 1
2 3 4 5 6 7 8
9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25 26 27 28 29
30 31 1 2 3 4 5

导航

统计

点击右上角即可分享
微信分享提示