SQLSERVER 分割字符串函数

原文地址：http://www.jb51.net/article/28921.htm

首先创建一个表值函数：

 

SET ANSI_NULLS ON 
GO 
SET QUOTED_IDENTIFIER ON 
GO 
/* 
by kudychen 2011-9-28 
*/ 
CREATE function [dbo].[SplitString] 
( 
@Input nvarchar(max), --input string to be separated 
@Separator nvarchar(max)=',', --a string that delimit the substrings in the input string 
@RemoveEmptyEntries bit=1 --the return value does not include array elements that contain an empty string 
) 
returns @TABLE table 
( 
[Id] int identity(1,1), 
[Value] nvarchar(max) 
) 
as 
begin 
declare @Index int, @Entry nvarchar(max) 
set @Index = charindex(@Separator,@Input) 
while (@Index>0) 
begin 
set @Entry=ltrim(rtrim(substring(@Input, 1, @Index-1))) 
if (@RemoveEmptyEntries=0) or (@RemoveEmptyEntries=1 and @Entry<>'') 
begin 
insert into @TABLE([Value]) Values(@Entry) 
end 
set @Input = substring(@Input, @Index+datalength(@Separator)/2, len(@Input)) 
set @Index = charindex(@Separator, @Input) 
end 
set @Entry=ltrim(rtrim(@Input)) 
if (@RemoveEmptyEntries=0) or (@RemoveEmptyEntries=1 and @Entry<>'') 
begin 
insert into @TABLE([Value]) Values(@Entry) 
end 
return 
end

调用示例： 

declare @str1 varchar(max), @str2 varchar(max), @str3 varchar(max) 
set @str1 = '1,2,3' 
set @str2 = '1###2###3' 
set @str3 = '1###2###3###' 
select [Value] from [dbo].[SplitString](@str1, ',', 1) 
select [Value] from [dbo].[SplitString](@str2, '###', 1) 
select [Value] from [dbo].[SplitString](@str3, '###', 0)