横向打印二叉树
https://www.luogu.com.cn/problem/P8603
构造树的过程不难,比较烦人的是如何把这棵树横着打印出来
...|-12 10-| ...|-8-| .......|...|-7 .......|-5-| ...........|-4
首先可以发现,打印的顺序是中序遍历,打印的过程可以在中序遍历的基础上修改
class TreeNode: def __init__(self, value): self.value = value self.left = None self.right = None class Tree: def __init__(self, arr): self.root = TreeNode(None) for num in arr: self.insert(num) self.middle_order() def insert(self, value): cur_node = self.root while cur_node.value is not None: cur_node = cur_node.left if value < cur_node.value else cur_node.right cur_node.value = value cur_node.left = TreeNode(None) cur_node.right = TreeNode(None) def middle_order(self, node=None, per_print='', location=''): """ :param node: :param per_print: :param location: a string represent location of the node, '0' represent left and '1' represent right :return: """ new_per_print = list(per_print) indexes = [i for i, c in enumerate(new_per_print) if c == '|'] # all indexes of '|' for i in range(len(location) - 1): if location[i] == location[i + 1]: new_per_print[indexes[i]] = '.' new_per_print = ''.join(new_per_print) if node is None: node = self.root to_print = str(node.value) + '-|' elif node.left.value is None and node.right.value is None: to_print = '-' + str(node.value) print(new_per_print + to_print) return else: to_print = '-' + str(node.value) + '-|' s_len = len(to_print) - 1 if node.right.value is not None: self.middle_order(node.right, per_print=per_print + '.' * s_len + '|', location=location + '1') print(new_per_print + to_print) if node.left.value is not None: self.middle_order(node.left, per_print=per_print + '.' * s_len + '|', location=location + '0') nums = [int(_) for _ in input().split()] t = Tree(nums)
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