【LeetCode 104_二叉树_遍历】Maximum Depth of Binary Tree

解法一：递归

1 int maxDepth(TreeNode* root)
2 {
3     if (root == NULL)
4         return 0;
5 
6     int max_left_Depth = maxDepth(root->left);
7     int max_right_Depth = maxDepth(root->right);
8     return max(max_left_Depth, max_right_Depth) + 1;
9 }

解法二：BFS

 1 int maxDepth(TreeNode* root)
 2 {
 3     if (root == NULL)
 4         return 0;
 5 
 6     queue<TreeNode*> node_queue;
 7     node_queue.push(root);
 8 
 9     int count = 0;
10     while (!node_queue.empty()) {
11         count++;
12         int len = node_queue.size();
13         for (int i = 0; i < len; ++i) {
14             TreeNode *node = node_queue.front();
15             node_queue.pop();
16 
17             if (node->left)
18                 node_queue.push(node->left);
19             if (node->right)
20                 node_queue.push(node->right);
21         }
22     }
23     return count;
24 }

 

posted @ 2015-07-05 17:18  QingLiXueShi  阅读(143)  评论(0)  编辑  收藏  举报