卡牌游戏

卡牌游戏

个人信息：就读于燕大本科软件project专业 眼下大三;

本人博客：google搜索“cqs_2012”就可以;

个人爱好：酷爱数据结构和算法。希望将来从事算法工作为人民作出自己的贡献;

编程语言：C++ 和 java ;

编程坏境：Windows 7 专业版 x64;

编程工具：vs2008;

制图工具：office 2010 powerpoint;

硬件信息：7G-3 笔记本;

真言

敢于承认不足。敢于去接触和学习，同一时候又沉稳而镇静

题目

百练 1003

How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can make the top card overhang the bottom one by half a card length, and the bottom one overhang the table by a third of a card length, for a total maximum overhang of 1/2 + 1/3 = 5/6 card lengths. In general you can make n cards overhang by 1/2 + 1/3 + 1/4 + ... + 1/(n + 1) card lengths, where the top card overhangs the second by 1/2, the second overhangs tha third by 1/3, the third overhangs the fourth by 1/4, etc., and the bottom card overhangs the table by 1/(n + 1). This is illustrated in the figure below.

输入

The input consists of one or more test cases, followed by a line containing the number 0.00 that signals the end of the input. Each test case is a single line containing a positive floating-point number c whose value is at least 0.01 and at most 5.20; c will contain exactly three digits.

输出

For each test case, output the minimum number of cards necessary to achieve an overhang of at least c card lengths. Use the exact output format shown in the examples. 

代码 java

//package packageTest;

import java.io.*;
import java.util.*;
public class Main
{            
	public static void main(String args[]) throws Exception
	{                    
		Scanner cin = new Scanner(System.in);
		double a = cin.nextDouble();
		while(a != 0)
		{
			my_1003(a);
			a = cin.nextFloat();
		}
		
	}
	
	public static void my_1003(double sum)
	{
		
		double result = 0.5 ;
		double i = 2;
		//System.out.println(sum);
		while(result <sum)
		{
			//System.out.println(result+" "+i);
			i++;
			result = result + (1/i) ;
			
		}
		
		System.out.println( (int)(i-1) +" card(s)");
	}
}