hdu 5078(2014鞍山现场赛 I题)

数据 表示每次到达某个位置的坐标和时间 计算出每对相邻点之间转移的速度（两点间距离距离/相隔时间） 输出最大值


Sample Input
2
5
2 1 9//t x y
3 7 2
5 9 0
6 6 3
7 6 0
10
11 35 67
23 2 29
29 58 22
30 67 69
36 56 93
62 42 11
67 73 29
68 19 21
72 37 84
82 24 98

Sample Output
9.2195444573
54.5893762558

 

 1 # include <iostream>
 2 # include <cstdio>
 3 # include <cstring>
 4 # include <algorithm>
 5 # include <string>
 6 # include <cmath>
 7 # include <queue>
 8 # include <list>
 9 # define LL long long
10 using namespace std ;
11 
12 struct Point
13 {
14     double x,y,t;
15 
16 }p[1010];
17 
18 double dist(Point a,Point b)
19 {
20     return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));
21 }
22 
23 int main()
24 {
25     //freopen("in.txt","r",stdin) ;
26     int T ;
27     scanf("%d" , &T) ;
28     while(T--)
29     {
30         int n ;
31         scanf("%d" , &n) ;
32         int i ;
33         double Max = 0 ;
34         for (i = 0 ; i < n ; i++)
35         {
36             scanf("%lf %lf %lf" , &p[i].t , &p[i].x , &p[i].y) ;
37         }
38         for (i = 0 ; i < n-1 ; i++)
39         {
40             double t = dist(p[i], p[i+1]) ;
41             t = t / (p[i+1].t - p[i].t) ;
42             if (t > Max)
43                 Max = t ;
44         }
45         printf("%.10lf\n" , Max) ;
46 
47 
48 
49     }
50     return 0;
51 }
View Code

 

posted @ 2015-10-01 21:17  __Meng  阅读(210)  评论(0)  编辑  收藏  举报