CF 579A (二进制拆分)

在培养皿中,每个细胞每天会繁殖,数量*2
我们可以在任意天加入任意数量的细胞入培养皿中。
想要知道最少加入多少个细胞,可以使得有一天,培养皿中细胞的数量会恰好为x

其实就是输出X的二进制中有多少个1

Sample test(s)
input
5
output
2
input
8
output
1

 

 1 # include <iostream>
 2 # include <cstdio>
 3 # include <cstring>
 4 # include <algorithm>
 5 # include <string>
 6 # include <cmath>
 7 # include <queue>
 8 # include <list>
 9 # define LL long long
10 using namespace std ;
11 
12 
13 
14 int main()
15 {
16     //freopen("in.txt","r",stdin) ;
17     int n ;
18     while(scanf("%d",&n) != EOF)
19     {
20         int sum = 0 ;
21         while(n)
22         {
23             if (n & 1)
24                 sum++ ;
25             n >>= 1 ;
26         }
27         printf("%d\n" , sum) ;
28     }
29 
30 
31 
32     return 0;
33 }
View Code

 

posted @ 2015-09-24 21:15  __Meng  阅读(1651)  评论(0编辑  收藏  举报