week日期的函数

 

如下是 hive的函数

 

select dayofweek ('2022-02-27') ; --dayofweek展示的是周几 共计 7个值 ， 6代表周五

=1

select weekofyear('2022-12-22') ;
--51

 

 

 

如下为mysql 的语句 ：


SELECT   
    WEEK(purchase_date) - WEEK('2023-11-01') + 1 week_of_month,  --用hive替换的话用weekofyear
    purchase_date,
    SUM(amount_spend) total_amount
FROM Purchases p
WHERE SUBSTRING(purchase_date,1,7)= '2023-11'
AND DAYOFWEEK(purchase_date) = 6                                 -- hive 也用dayofweek
GROUP BY purchase_date
ORDER BY week_of_month ASC
;

作者：没上岸就继续刷呗
链接：https://leetcode.cn/problems/friday-purchases-i/solutions/2785252/jian-dan-si-lu-by-eager-mooreli2-v4ce/
来源：力扣（LeetCode）
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