使用Dom4j解析XML文件

public static String readXMl(){
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    String s = null;
    try{
        DocumentBuilder db = dbf.newDocumentBuilder();
        Document document = db.parse("classpath:linuxFile.xml");
      //  s = document.getElementById("file").getNodeValue();
        NodeList node = document.getElementsByTagName("temporary_file");
        for (int i = 0;i<node.getLength();i++){
            Element son = (Element)node.item(i);
            for (Node node1 = son.getFirstChild(); node1 != null; node1 = node1.getNextSibling()){
                if (node1.getNodeType() == Node.ELEMENT_NODE){
                    String name = node1.getNodeName();
                    String value = node1.getFirstChild().getNodeValue();
                    if(name.equals("filePath")){
                        s = value;
                    }
                }
            }
        }
    }catch (Exception e){
        e.printStackTrace();
    }


    return s;
}

<?xml version="1.0" encoding="UTF-8"?>
<temporary_file>
    <filePath>E:\ff</filePath>
</temporary_file>