asp.net ajax实现在线人员的显示

vs2005+ajax要实现以前的效果实在是太简单啦.主要大家熟悉了AJAX Extensions几个控件.做起来就是跟以前的效果一样

 

大家见code吧

 

<%@ Page Language="C#" AutoEventWireup="true" CodeFile="TTimer.aspx.cs" Inherits="TTimer" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
    <title>无标题页</title>
</head>
<body>
    <form id="form1" runat="server">
    <div>
        <asp:ScriptManager ID="ScriptManager1" runat="server">
        </asp:ScriptManager>
        <asp:UpdatePanel ID="UpdatePanel1" runat="server">
            <ContentTemplate>
                <asp:Timer ID="Timer1" runat="server" OnTick="Timer1_Tick">
                </asp:Timer>
                <asp:GridView ID="GridView1" runat="server">
                </asp:GridView>
            </ContentTemplate>
        </asp:UpdatePanel>
   
    </div>
    </form>
</body>
</html>

 

 

 

using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;

public partial class TTimer : System.Web.UI.Page
{
    private DataSet ds = new DataSet();
    protected void Page_Load(object sender, EventArgs e)
    {
        if(!Page.IsPostBack)
        binddata();
    }
    private void binddata()
    {
        string sql = "select   Class_ID,Class_Name,Class_Pid   from   TC_User order   by   Class_ID ";
        string strconn = "Data Source=SEE-CLN-059\\PMSERVER;Initial Catalog=test;uid=sa;pwd=;";
        Conn conn = new Conn(strconn);

        ds = conn.GetSet(sql);
        this.GridView1.DataSource = ds.Tables[0];
        this.GridView1.DataBind();
    }
    protected void Timer1_Tick(object sender, EventArgs e)
    {
        binddata();
    }
}

当然遇到异常的情况请自己写异常错误显示吧...

posted @ 2008-07-21 16:09  meetweb  阅读(773)  评论(3编辑  收藏  举报