栈的作用之递归,波兰表达式——C语言描述

栈的作用之递归,波兰表达式——C语言描述

1 斐波拉契数列

公式:f(0) = 0, f(1) = 1, f(n) = f(n - 1) + f(n - 2);(n>2)

(1)循环实现

代码:

void FabByArr(void) {
	int i;
	int RecArr[5];

	RecArr[0] = 0;
	RecArr[1] = 1;	

	for (i = 2; i < 5; ++i) {
		RecArr[i] = RecArr[i - 2] + RecArr[i - 1];	
	}

	for (i = 0; i < 5; ++i) {
		printf("RecArr[%d] = %d\n", i, RecArr[i]);
	}
}

结果:

RecArr[0] = 0

RecArr[1] = 1

RecArr[2] = 1

RecArr[3] = 2

RecArr[4] = 3

(2)递归

​ 每调用一层函数时,就入栈,那层函数实现后就出栈

代码:

int FabRec(int i) {
	if (0 == i) {
		return 0;
	}
	else if (1 == i) {
		return 1; 
	}
	
	return FabRec(i - 2) + FabRec(i - 1);
}

void PrintFabByRec(void) {
	int i = 0;

	for (i = 0; i < 5; ++i) {
		printf("The %d value = %d\n", i, FabRec(i));
	}
}

结果:

The 0 value = 0

The 1 value = 1

The 2 value = 1

The 3 value = 2

The 4 value = 3

posted @ 2022-07-18 22:23  Meditators  阅读(52)  评论(0编辑  收藏  举报