kedaOJ#P0646. [NOIP2016提高组] 换教室
题目
P0646. [NOIP2016提高组] 换教室
思路
简单很难的D规划P
代码
#include<bits/stdc++.h>
using namespace std;
int dis[305][305];
constexpr int _SIZE = 2e3;
int n, m, v, e;
int c[_SIZE + 5], d[_SIZE + 5];
double k[_SIZE + 5];
double f[2][_SIZE + 5];
signed main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> n >> m >> v >> e;
memset(dis, 0x3f, sizeof dis);
for (int i = 1; i <= n; i++) cin >> c[i];
for (int i = 1; i <= n; i++) cin >> d[i];
for (int i = 1; i <= n; i++) cin >> k[i];
for (int i = 1; i <= v; i++) dis[i][i] = 0;
for (int i = 1; i <= e; i++) {
int u, v, l;
cin >> u >> v >> l;
int temp = min(dis[u][v], l);
dis[u][v] = dis[v][u] = temp;
}
for (int k = 1; k <= v; k++)
for (int i = 1; i <= v; i++)
for (int j = 1; j <= v; j++)
dis[i][j] = min(dis[i][j], dis[i][k] + dis[k][j]);
memset(f, 127, sizeof(f));
f[0][0] = 0, f[1][1] = 0;
for (int i = 2; i <= n; i++) {
for (int j = i; j >= 0; j--) {
f[0][j] = min(f[1][j] + k[i - 1] * dis[d[i - 1]][c[i]] +
(1 - k[i - 1]) * dis[c[i - 1]][c[i]],
f[0][j] + dis[c[i - 1]][c[i]]);
if (j == 0) continue;
f[1][j] = min(f[0][j - 1] + k[i] * dis[c[i - 1]][d[i]] +
(1 - k[i]) * dis[c[i - 1]][c[i]],
f[1][j - 1] + k[i - 1] * k[i] * dis[d[i - 1]][d[i]] +
k[i - 1] * (1 - k[i]) * dis[d[i - 1]][c[i]] +
(1 - k[i - 1]) * k[i] * dis[c[i - 1]][d[i]] +
(1 - k[i - 1]) * (1 - k[i]) * dis[c[i - 1]][c[i]]);
}
}
double ans = 1145141919810.0;
for (int i = 0; i <= m; i++) ans = min({ans, f[0][i], f[1][i]});
cout << fixed << setprecision(2) << ans << '\n';
return 0;
}
这是mcr130102的博客,转载请注明出处
· 分享一个免费、快速、无限量使用的满血 DeepSeek R1 模型,支持深度思考和联网搜索!
· 使用C#创建一个MCP客户端
· ollama系列1:轻松3步本地部署deepseek,普通电脑可用
· 基于 Docker 搭建 FRP 内网穿透开源项目(很简单哒)
· 按钮权限的设计及实现