第二十四周项目6-点和距离

读程序,写出函数的定义,注意其中枚举类型的用法。

enum SymmetricStyle {axisx,axisy,point};//分别表示按x轴, y轴, 原点对称
struct Point{
	double x;  // 横坐标
	double y;  // 纵坐标
};
double distance1(Point p1, Point p2);   // 两点之间的距离,如果用distance,将会与命名空间std中也已经定义的distance函数重名
double distance0(Point p1);
Point symmetricAxis(Point p,SymmetricStyle style);   //返回对称点
int main( ){
	Point p1={1,5},p2={4,1},p;
	cout<<"两点的距离为:"<<distance1(p1,p2)<<endl;
	cout<<"p1到原点的距离为:"<<distance0(p1)<<endl;
	p=symmetricAxis(p1,axisx);
	cout<<"p1关于x轴的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl;
	p=symmetricAxis(p1,axisy);
	cout<<"p1关于y轴的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl;
	p=symmetricAxis(p1,point);
	cout<<"p1关于原点的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl;
	return 0;
}
// 求两点之间的距离  
double distance1(Point p1,Point p2)  
{  
    double d;  
    ……  
    return d;  
}  
  
// 求点到原点的距离  
double distance0(Point p)  
{  
    double d;  
    ……  
    return d;  
}  
  
// 求对称点  
Point symmetricAxis(Point p1,SymmetricStyle style)  
{  
    Point p;  
    ……
    return p;  
}  

#include <iostream>
#include <Cmath>
using namespace std;

enum SymmetricStyle {axisx,axisy,point};//分别表示按x轴, y轴, 原点对称
struct Point
{
	double x;  // 横坐标
	double y;  // 纵坐标
};
double distance1(Point p1, Point p2);   // 两点之间的距离
double distance0(Point p1);
Point symmetricAxis(Point p,SymmetricStyle style);   //返回对称点

int main( )
{
	Point p1={1,5},p2={4,1},p;
	cout<<"两点的距离为:"<<distance1(p1,p2)<<endl;
	cout<<"p1到原点的距离为:"<<distance0(p1)<<endl;
	p=symmetricAxis(p1,axisx);
	cout<<"p1关于x轴的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl;
	p=symmetricAxis(p1,axisy);
	cout<<"p1关于y轴的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl;
	p=symmetricAxis(p1,point);
	cout<<"p1关于原点的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl;
	return 0;
}

// 求两点之间的距离
double distance1(Point p1,Point p2)
{
	double d;
	d=sqrt((p1.x-p2.x)*(p1.x-p2.x)+(p1.y-p2.y)*(p1.y-p2.y));
	return d;
}

// 求点到原点的距离
double distance0(Point p)
{
	double d;
	d=sqrt(p.x*p.x+p.y*p.y);
	return d;
}

// 求对称点
Point symmetricAxis(Point p1,SymmetricStyle style)
{
	Point p;
	p.x=p1.x;
	p.y=p1.y;
	switch(style)
	{
	case axisx:
		p.y=-p1.y; break;
	case axisy:
		p.x=-p1.x; break;
	case point:
		p.x=-p1.x;p.y=-p1.y;
	}
	return p;
}
运行结果:


@ Mayuko

posted @ 2015-03-05 17:19  麻麻麻麻鱼鱼  阅读(123)  评论(0编辑  收藏  举报