Codeforces Round #428A
题意:A每天可以得到ai颗糖,每天A最多可以给B8颗糖,A的糖可以结余,问最少多少天可以B可以得到k颗糖
思路:没什么好说的
AC代码:
#include "iostream" #include "iomanip" #include "string.h" #include "stack" #include "queue" #include "string" #include "vector" #include "set" #include "map" #include "algorithm" #include "stdio.h" #include "math.h" #pragma comment(linker, "/STACK:102400000,102400000") #define bug(x) cout<<x<<" "<<"UUUUU"<<endl; #define mem(a,x) memset(a,x,sizeof(a)) #define step(x) fixed<< setprecision(x)<< #define mp(x,y) make_pair(x,y) #define pb(x) push_back(x) #define ll long long #define endl ("\n") #define ft first #define sd second #define lrt (rt<<1) #define rrt (rt<<1|1) using namespace std; const long long INF = 1e18+1LL; const int inf = 1e9+1e8; const int N=1e5+100; const ll mod=1e9+7; int n,k; int main(){ ios::sync_with_stdio(0),cin.tie(0),cout.tie(0); cin>>n>>k; int t=0,l=0; for(int i=1; i<=n; ++i){ int x; cin>>x; l+=x; if(l>=8){ t+=8; l-=8; } else{ t+=l; l=0; } if(t>=k){ cout<<i; return 0; } } cout<<-1; return 0; }