摘要: #include <stdio.h>#include <stdlib.h>void parse_arg(const int argc, const char **argv, const char **src, char const **dest, int *num){ if(argc != 4){ fprintf(stderr, "%s <number> <src_filename> <dest_filename>\n", argv[0]); exit(1); } *num = atoi(argv[1]); *sr 阅读全文
posted @ 2012-09-16 20:05 庄庄庄 阅读(3605) 评论(0) 推荐(0) 编辑