摘要: (2014北约自主招生)已知正实数$x_1,x_2,\cdots,x_n$满足$x_1x_2\cdots x_n=1,$求证: $(\sqrt{2}+x_1)(\sqrt{2}+x_2)\cdots(\sqrt{2}+x_n)\ge(\sqrt{2}+1)^n$ 阅读全文
posted @ 2019-03-06 19:08 M.T 阅读(369) 评论(0) 推荐(0) 编辑