摘要: int id(int x,int y,int m){ //m列 return m*(x-1)+y; } pii rid(int u,int m){ int x=(u+m-1)/m;//m列 int y=u%m;if(y==0)y+=m; return make_pair(x,y); } 阅读全文
posted @ 2024-02-28 21:32 potential-star 阅读(75) 评论(0) 推荐(0)