Add Two Numbers

First post here, : )

Problem

Add Two Numbers from http://www.leetcode.com/onlinejudge

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8

This problem is easy, it 's a practice for traversing the list by using ListNode class the problem given. 

1: go through two list

2:combine those two list(need ti be careful for handling Carry digit and one number is longer than other  )

3:print answer

public class ListNode
{
 int val;
 ListNode next;

 ListNode(int x)
 {
  val = x;
  next = null;
 }

 public ListNode addTwoNumbers(ListNode l1, ListNode l2)
 {
  ListNode head = new ListNode(-1), p = head;

  ListNode A = l1;
  ListNode B = l2;

  int jin = 0;
  while ((A != null || B != null) || jin > 0)
  {
   int x = 0;

   if (A == null && B == null)
   {
    ListNode tmp = new ListNode(jin);
    p.next = tmp;
    p = tmp;
    break;
   }

   if (A == null && B != null)
   {
    x = B.val + jin;
    jin = x / 10;
    x = x % 10;

    ListNode tmp = new ListNode(x);
    p.next = tmp;
    p = tmp;
    B = B.next;
    continue;
   }
   if (A != null && B == null)
   {
    x = A.val + jin;
   jin = x / 10;
    x = x % 10;
    ListNode tmp = new ListNode(x);
    p.next = tmp;
    p = tmp;
    A = A.next;
    continue;
   }
   x = A.val + B.val + jin; jin = x / 10;
   x = x % 10;
   ListNode tmp = new ListNode(x);
   p.next = tmp;
   p = tmp;
   A = A.next;
   B = B.next;
  }
  return head.next;
 }

}