WorkPool线程池
WorkPool线程池
就是限制函数的运行数量的struct
参考https://jiajunhuang.com/articles/2020_04_21-golang_concurrency.md.html
package pool
type GoPool struct {
MaxLimit int
tokenChan chan struct{}
}
type GoPoolOption func(*GoPool)
func WithMaxLimit(max int) GoPoolOption {
return func(gp *GoPool) {
gp.MaxLimit = max
gp.tokenChan = make(chan struct{}, gp.MaxLimit)
for i := 0; i < gp.MaxLimit; i++ {
gp.tokenChan <- struct{}{}
}
}
}
func NewGoPool(options ...GoPoolOption) *GoPool {
p := &GoPool{}
for _, o := range options {
o(p)
}
return p
}
// Submit will wait a token, and then execute fn
func (gp *GoPool) Submit(fn func()) {
token := <-gp.tokenChan // if there are no tokens, we'll block here
go func() {
fn()
gp.tokenChan <- token
}()
}
// Wait will wait all the tasks executed, and then return
func (gp *GoPool) Wait() {
for i := 0; i < gp.MaxLimit; i++ {
<-gp.tokenChan
}
close(gp.tokenChan)
}
func (gp *GoPool) size() int {
return len(gp.tokenChan)
}
实现原理
池子里面的属性是令牌桶,这个桶子用有缓冲chan来实现,实现了自动阻塞
带有接口那味的实现
workpool.go
package work
// 什么是池子,池子就是他一直有地址空间,你上传就Ok了
// 方法:
// 上传 + 执行任务
// 当前任务空闲
// 属性: 令牌桶
type IWorkPool interface {
Submit(work IWork)
GetWorkCount() int
}
type WorkPool struct {
Tocken chan int
}
func NewWorkPool(limit int) *WorkPool {
wp := &WorkPool{
Tocken:make(chan int, limit),
}
for i := 0; i < limit; i++ {
wp.Tocken<- i
}
return wp
}
func (wp *WorkPool) Submit(work IWork) {
<- wp.Tocken
go func() {
work.DoWork()
wp.Tocken<-1
}()
}
func (wp *WorkPool) GetWorkCount() int {
return len(wp.Tocken)
}
work.go
package work
import "fmt"
// 属性:
// work func()
//方法:
// DoWork()
type IWork interface {
DoWork()
}
// 具体任务
type Work struct {
work func()
}
func NewWork(fn func()) *Work {
return &Work{
work: fn,
}
}
func (w *Work) DoWork() {
w.work()
fmt.Println("任务ok")
}
测试代码
package main
import (
"go-newbase/work"
"time"
)
func main() {
pool := work.NewWorkPool(4)
for i := 0; i < 100; i++ {
newWork := work.NewWork(func() {
time.Sleep(3 * time.Second)
})
pool.Submit(newWork)
}
//time.Sleep(time.Second * 3)
time.Sleep(10000 * time.Second)
}