Luogu P4097 [HEOI2013]Segment 李超线段树

题目链接 \(Click\) \(Here\)

李超线段树的模板。但是因为我实在太\(Naive\)了，想象不到实现方法。

看代码就能懂的东西，放在这里用于复习。

#include <bits/stdc++.h>
using namespace std;

const int N = 100010;
#define ls (p << 1)
#define rs (p << 1 | 1)
#define mid ((l + r) >> 1)
				 
struct Node {
    int l, r, id;
    double yl, yr;
    Node (int x1 = 0, int y1 = 0, int x2 = 0, int y2 = 0, int i = 0) {
        l = x1, r = x2, yl = y1, yr = y2, id = i;
        if (l == r) {
			yl = yr = max (yl, yr);
		}
    }
    double get (int x) {return l == r ? yl : yl + (k () * (x - l));}
    double k () {return (yr - yl) / (r - l);}
    void lm (int x) {yl = get (x); l = x;}
    void rm (int x) {yr = get (x); r = x;}
};

bool hei (Node a, Node b, int x) {
    return a.get (x) == b.get (x) ? a.id < b.id : a.get (x) > b.get (x);
}

struct St {
    Node tree[N << 2];

	void build (int l, int r, int p) {
        tree[p].l = l;
		tree[p].r = r;
        if (l == r) return;
        build (l, mid, ls);
        build (mid + 1, r, rs); 
    }
	
    Node query (int t, int l, int r, int p) {
        if (l == r) return tree[p];
		Node res;
        if (t <= mid) {
			res = query (t, l, mid, ls);
        } else {
			res = query (t, mid + 1, r, rs);
		}
		return hei (res, tree[p], t) ? res : tree[p];
    }
	
    void update (int l, int r, Node k, int p) {
        if (tree[p].l > k.l) k.lm (tree[p].l);
        if (tree[p].r < k.r) k.rm (tree[p].r); //削足适履
        if (hei (k, tree[p], mid)) swap (tree[p], k); //让tree[p]在mid上具有优势
        if (min (tree[p].yl, tree[p].yr) >= max (k.yl, k.yr)) return; //如果完全覆盖
        if (l == r) return; //如果大小为1
        if (tree[p].k () <= k.k ()) {
			update (mid + 1, r, k, rs); //如果k在后面有露出来的情况
        } else {
			update (l, mid, k, ls); //如果k在前面有露出来的情况
		}
	}
	
    void insert (int l, int r, Node k, int p) {
        if (k.l > r || k.r < l) return;
        if (tree[p].l > k.l) k.lm (tree[p].l);
        if (tree[p].r < k.r) k.rm (tree[p].r);
        if (l == k.l && r == k.r) {
			update (l, r, k, p);
			return;
		}
		//把node一路传下去，对应区间就削成对应大小的线段
        if (l == r) return;
		insert (l, mid, k, ls);
		insert (mid + 1, r, k, rs);
    }
}T;

const int My = 1e9;
const int Mx = 39989;

int m, k, la, Ind, opt;

int main () {
    T.build (1, Mx, 1);
    cin >> m;
    while (m--) {
        cin >> opt;
        if (opt == 0) {
            cin >> k;
            k = (k + la - 1) % Mx + 1;
            la = T.query (k, 1, Mx, 1).id;
            cout << la << endl;
        } else {
            int x0, x1, y0, y1;
            cin >> x0 >> y0 >> x1 >> y1;
            x0 = (x0 + la - 1) % Mx + 1;
			x1 = (x1 + la - 1) % Mx + 1;
            y0 = (y0 + la - 1) % My + 1;
			y1 = (y1 + la - 1) % My + 1;
            if (x0 > x1) {
				swap (x0, x1);
				swap (y0, y1);
			}
            Node res = Node (x0, y0, x1, y1, ++Ind);
            T.insert (1, Mx, res, 1);
        }
    }
}