摘要:
SELECT base.* from(select id_no,COUNT(*) from aim.aim_t_cust_base GROUP BY id_no HAVING COUNT(*) >1) as t left join aim.aim_t_cust_base base on t.id_n
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posted @ 2019-06-12 14:52
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摘要:
实例1: SET @ID = 0; SELECT AVG(loan_amount) from ( SELECT @ID:=@ID+1 as ID, loan_amount FROM table_xxx ORDER BY loan_amount ) a where IF( ROUND(@ID/2,0)
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posted @ 2019-06-12 11:37
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