laravel框架之状态更改

//表单
@if($v['sex']==0)
<td class="se" ss="{{$v['sex']}}" id="{{$v['id']}}" >男</td>
@elseif($v['sex']==1)
<td class="se" ss="{{$v['sex']}}" id="{{$v['id']}}" >女</td>

@endif

//jqery
$(document).on("click",".se",function () {
id=$(this).attr("id");
sex= $(this).attr("ss");
str="";
if (sex==0){
str="男"
}else{
str="女"
}

that=$(this);
$.ajax({
url:"jdjg",
type:"post",
dataType:"json",
data:{
id:id,
sex:str
},
success:function (data) { console.log(data);
if (data=="男"){
that.text("男")
that.attr("ss",0)
} else{
that.text("女")
that.attr("ss",1)
}


}
})
})



//控制器
function   jdjg(req $req){
$id= $req->post("id");
$sex=$req->post("sex");
// echo json_encode($sex);die;
if ($sex=="男"){
$res=DB::table("poker")->where("id",$id)->update(["sex"=>1]);
$sex="女";
echo json_encode($sex);
}else{

$res=DB::table("poker")->where("id",$id)->update(["sex"=>0]);
$sex="男";
echo json_encode($sex);
}






posted @ 2019-07-14 21:28  php毛宏历的博客  阅读(518)  评论(0编辑  收藏  举报