合并两个或多个有序链表

合并两个有序链表:

法一:迭代

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
package main
 
func mergeTwoLists(list1 *ListNode, list2 *ListNode) *ListNode {
   dummyHead := &ListNode{}
   cursor := dummyHead
   for list1 != nil && list2 != nil {
      if list1.Val < list2.Val {
         cursor.Next = list1
         list1 = list1.Next
      } else {
         cursor.Next = list2
         list2 = list2.Next
      }
      cursor = cursor.Next
   }
   if list1 == nil {
      cursor.Next = list2
   } else {
      cursor.Next = list1
   }
   return dummyHead.Next
} 

法二:递归

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
package main
 
func mergeTwoLists(list1 *ListNode, list2 *ListNode) *ListNode {
   if list1 == nil {
      return list2
   } else if list2 == nil {
      return list1
   } else if list1.Val < list2.Val {
      list1.Next = mergeTwoLists(list1.Next, list2)
      return list1
   } else {
      list2.Next = mergeTwoLists(list1, list2.Next)
      return list2
   }
}

  

合并多个有序链表:

法一:分治法

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
/**
 * Definition for singly-linked list.
 * type ListNode struct {
 *     Val int
 *     Next *ListNode
 * }
 */
func mergeKLists(lists []*ListNode) *ListNode {
    var pre, cur *ListNode
    n := len(lists)
    for i := 0; i < n; i++ {
        if i == 0 {
            pre = lists[i]
            continue
        }
        cur = lists[i]
        pre = merge(pre, cur)
    }
    return pre
}
 
func merge(l1, l2 *ListNode) *ListNode {
    head := &ListNode{}
    cur := head
    for l1 != nil || l2 != nil {
        if l1 != nil && l2 != nil {
            if l1.Val < l2.Val {
                cur.Next = l1
                l1 = l1.Next
            } else {
                cur.Next = l2
                l2 = l2.Next
            }
            cur = cur.Next
        } else if l1 != nil {
            cur.Next = l1
            break
        } else {
            cur.Next = l2
            break
        }
    }
    return head.Next
}

 法二:小根堆

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
func mergeKLists(lists []*ListNode) *ListNode {
    k := len(lists)
    h := new(minHeap)
    for i := 0; i < k; i++ {
        if lists[i] != nil {
            heap.Push(h, lists[i])
        }
    }
 
    dummyHead := new(ListNode)
    pre := dummyHead
    for h.Len() > 0 {
        tmp := heap.Pop(h).(*ListNode)
        if tmp.Next != nil {
            heap.Push(h, tmp.Next)
        }
 
        pre.Next = tmp
        pre = pre.Next
    }
 
    return dummyHead.Next
}
 
type minHeap []*ListNode
 
func (h minHeap) Len() int           { return len(h) }
func (h minHeap) Less(i, j int) bool { return h[i].Val < h[j].Val }
func (h minHeap) Swap(i, j int)      { h[i], h[j] = h[j], h[i] }
func (h *minHeap) Push(x interface{}) {
    // Push and Pop use pointer receivers because they modify the slice's length,
    // not just its contents.
    *h = append(*h, x.(*ListNode))
}
func (h *minHeap) Pop() interface{} {
    old := *h
    n := len(old)
    x := old[n-1]
    *h = old[0 : n-1]
    return x
}

  

 

posted @   ☞@_@  阅读(36)  评论(0编辑  收藏  举报
相关博文:
阅读排行:
· 阿里最新开源QwQ-32B,效果媲美deepseek-r1满血版,部署成本又又又降低了!
· SQL Server 2025 AI相关能力初探
· 单线程的Redis速度为什么快?
· AI编程工具终极对决:字节Trae VS Cursor,谁才是开发者新宠?
· 开源Multi-agent AI智能体框架aevatar.ai,欢迎大家贡献代码
点击右上角即可分享
微信分享提示