HttpPost请求将json作为请求体传入的简单处理方法

通过httpclient的post方法发送json参数进行接口测试。借鉴知乎上“云层”的提供的方法。

作者：云层
链接：https://www.zhihu.com/question/30878548/answer/121149629
来源：知乎

把要发送的json作为字符串传入body即可

public static String sendHttpPost(String url, String body) throws Exception {
CloseableHttpClient httpClient = HttpClients.createDefault();
HttpPost httpPost = new HttpPost(url);
httpPost.addHeader("Content-Type", "application/json");
httpPost.setEntity(new StringEntity(body));

CloseableHttpResponse response = httpClient.execute(httpPost);
System.out.println(response.getStatusLine().getStatusCode() + "\n");
HttpEntity entity = response.getEntity();
String responseContent = EntityUtils.toString(entity, "UTF-8"); 
System.out.println(responseContent);

response.close();
httpClient.close();
return responseContent;
}

 

我的测试代码示例：

    public static void main(String[] args) {
        //测试公司的API接口，将json当做一个字符串传入httppost的请求体
        String result = null;
        HttpClient client = HttpClients.createDefault();
        URIBuilder builder = new URIBuilder();
        URI uri = null;
        try {
            uri = builder.setScheme("http")
                      .setHost("xxx.xxx.xxx.xxx:xxxx")
                      .setPath("/api/authorize/login")
                      .build();
            
            HttpPost post = new HttpPost(uri);
            //设置请求头
            post.setHeader("Content-Type", "application/json");
            String body = "{\"Key\": \"\",\"Secret\": \"\"}";
            //设置请求体
            post.setEntity(new StringEntity(body));
            //获取返回信息
            HttpResponse response = client.execute(post);
            result = response.toString();
        } catch (Exception e) {
            System.out.println("接口请求失败"+e.getStackTrace());
        }
        System.out.println(result);
    }