react中redux的详细使用

如何使用redux

1.在src index.js

   import React from 'react';
   import ReactDOM from 'react-dom'

   import App from './components/app.jsx'
   import store from './redux/store'

   function render() {
       ReactDOM.render(<App store={store} />,document.getElementById('root'))
       
   }

   render()

   store.subscribe(() =>{
       render()
   })

2.在src目录下新建redux文件夹

3.在redux目录下新建store.js,reducers.js,actions,action_type.js

store.js

  import {createStore} from 'redux'
   import {counter} from './reducers.js'
   const store = createStore(counter);
   console.log(store,store.getState())

   export default store

reducers.js

import {INCREMENT,DECREMENT} from './action_type.js'
export const counter = (state =0,action) =>{
    console.log('counter',state,action)
    switch (action.type) {
        case INCREMENT:
            return state + action.data

     case DECREMENT:
            return state - action.data
            
        default:
           return state
    }

}

actions.js

    import {INCREMENT,DECREMENT} from './action_type'

    //增加
    export const increment =(number) => ({type:INCREMENT,data:number})

    //减少
    export const decrement =(number) => ({type:DECREMENT,data:number})

action_type.js

export const INCREMENT = 'INCREMENT'
export const DECREMENT = 'DECREMENT'

app.jsx(src >components >app.jsx)

import React, { Component } from 'react';
import * as actions from '../redux/actions'

export default class App extends Component {

    increment = () =>{
        
        //1.得到选择增加数量
        const number = this.selsectVal.value*1

        this.props.store.dispatch(actions.increment(number))

    }

    decrement =() =>{

          //1.得到选择增加数量
        const number = this.selsectVal.value*1

        this.props.store.dispatch(actions.decrement(number))


    }

    incrementIfOdd =() =>{
          //1.得到选择增加数量
          const number = this.selsectVal.value*1;
         //console.log(this.props.store)

          //2.得到原本的count状态
          const count = this.props.store.getState() 

          //判断,满足条件才更新状态
          if(count % 2 ===1){ //是奇数

        
        this.props.store.dispatch(actions.increment(number))


        }

    }

    incrementAsync =() =>{

         //1.得到选择增加数量
         const number = this.selsectVal.value*1

        //  //2.得到原本的count状态,并计算新的count
        //  const count = this.state.count 

         setTimeout(() => {

        
        this.props.store.dispatch(actions.increment(number))

             
         }, 200);


    }

    render(){
        const count = this.props.store.getState();
        // console.log(count)
        return (
            <div>
                <p>click {count} times</p>

                <div>
                    <select ref={val => this.selsectVal = val}>
                        <option value="1">1</option>
                        <option value="2">2</option>
                        <option value="3">3</option>
                    </select>&nbsp;

                    <button onClick={this.increment}>+</button>&nbsp;
                    <button onClick={this.decrement}>-</button>&nbsp;
                    <button onClick={this.incrementIfOdd}>increment if odd</button>&nbsp;
                    <button onClick={this.incrementAsync}>increment async</button>

                </div>
            </div>
        )
    }
}

问题

1.redux与react组件的代码耦合度太高

2.代码不够简洁